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4 years ago

14

A library had 6422 music CDs stored on 26 shelves. If the same number of CDs were stored on each shelf, how many CDs were stored

on each shelf?

2 answers:

sattari [20]4 years ago

8 0

Simply divide the number of CDs by the number of shelves. 6422 / 26 = 247 247 CDs per shelf.

Semenov [28]4 years ago

8 0

Divide 6422 by 26
And you will get 247
Therefore,there is 247 CDs on each shelf

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In triangle ABC, a=31 , b=22 , c=18. Identify m∠A rounded to the nearest degree.

Veronika [31]

Answer:

101

Step-by-step explanation:

According to the Law of Cosines, for any △ABC with side lengths a, b, and c, a2=b2+c2−2bccosA; b2=a2+c2−2accosB; and c2=a2+b2−2abcosC

.

The Law of Cosines can be used because all three side lentghs are known.

Set up the equation for the Law of Cosines:

a2=b2+c2−2bccosA

Substitute the known values into the Law of Cosines:

312=222+182−2(22)(18)cosA

Square the values and multiply:

961=484+324−792cosA

Add:

961=808−792cosA

Subtract 808

from both sides:

153=−792cosA

Divide both sides by −792

:

153−792=cosA

According to this equation m∠A

is equal to the inverse cosine function of −153792

. Write this:

m∠A=cos−1(−153792)

Calculate the value of the inverse cosine −153792

on a calculator:

m∠A≈101°

Therefore, m∠A≈101°

.

8 0

3 years ago

3. Francis has an unpaid balance of $480 on his credit card.

GarryVolchara [31]

Answer:

4 dollars 80 cents

Step-by-step explanation:

if annual is 12%, find monthly, 12/12=1

monthly rate is 1%

convert to decimal

0.01

480*0.01

4.8

6 0

3 years ago

What is the equation of this line in slope-intercept form? y=−3x−1y=−3x−1 y=−13x−1y=−13x−1 y=3x−1y=3x−1 y = 3x + 1

aalyn [17]

(y+1)=3(x-1) is the answer to your problem

4 0

3 years ago

A coin bank that excepts only nickels and dimes contains $9.15. There are three more than twice as many nickels as there are dim

valentinak56 [21]

45 dimes and 93 nickels were in bank

<em><u>Solution:</u></em>

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

$n \times 0.05 + d \times 0.10 = 9.15$

0.05n + 0.10d = 9.15 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

0.15 + 0.1d + 0.10d = 9.15

0.2d = 9

<h3>d = 45</h3>

From eqn 1

n = 3 + 2(45)

n = 3 + 90 = 93

<h3>n = 93</h3>

Thus 45 dimes and 93 nickels were in bank

3 0

4 years ago

Find two positive consecutive integers whose product is 132.

iren2701 [21]

If x is the first integer, then x+1 is the second. x(x+1)=132 or x^2+x-132=0. This factors as (x-11)(x+12)=0. Thus either x=11 or x=-12
<span>So either 11 and 12 or -12 and -11 will do.</span>

7 0

3 years ago