His estimate is not reasonable because he would have to be more descriptive in order to have his answer justified
Answer:
A = (Z-CD - EFG)/B
Step-by-step explanation:
AB + CD + EFG = Z.
Subtract CD and EFG from each side
AB + CD + EFG-CD -EFG = Z-CD - EFG
AB = Z-CD - EFG
Divide each side by B
AB /B = (Z-CD - EFG)/B
A = (Z-CD - EFG)/B
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
Group 1:
μ1 = 59.7
s1 = 2.8
n1 = sample size = 12
Group 2:
μ2 = 64.7
s2 = 8.3
n2 = sample size = 15
α = 0.1
Assume normal distribution and equ sample variance
A.)
Null and alternative hypothesis
Null : μ1 = μ2
Alternative : μ1 < μ2
B.)
USing the t test
Test statistic :
t = (m1 - m2) / S(√1/n1 + 1/n2)
S = √(((n1 - 1)s²1 + (n2 - 1)s²2) / (n1 + n2 - 2))
S = √(((12 - 1)2.8^2 + (15 - 1)8.3^2) / (12 + 15 - 2))
S = 6.4829005
t = (59.7 - 64.7) / 6.4829005(√1/12 + 1/15)
t = - 5 / 2.5108165
tstat = −1.991384
Decision rule :
If tstat < - tα, (n1+n2-2) ; reject the Null
tstat < t0.1,25
From t table :
-t0.1, 25 = - 1.3163
tstat = - 1.9913
-1.9913 < - 1.3163 ; Hence reject the Null
3x-14=4x-9
-4x -4x
-x-14=-9
-14 -14
-x=-15
-x/-1=-15/-1
x=15
Sorry if this is a bit confusing, but I hope I helped
