
<u>Answer</u><u>:</u>
<u>a.</u><u> </u><u>7</u>
Hope you could understand.
If you have any query, feel free to ask.
<h3>
Answer: 49</h3>
Work Shown:
Replace x with 3, replace y with -8. Use order of operations PEMDAS to simplify.
x^2 + y^2 + x*y
3^2 + (-8)^2 + 3*(-8)
9 + 64 - 24
73 - 24
49
debt is greater than 25
you owe more than 25 dollars
<h3>:- Solution</h3>
-8x - 9 > -21
Move -9 to right side
-8x > -21 + 9
-8x > -12
x < -12/-8
x < 3/2
the answer to -8x - 9 > -21 is <u>x</u><u> </u><u><</u><u> </u><u>3</u><u>/</u><u>2</u>
Answer:
285.6 square units
Step-by-step explanation:
The shaded area can be described a a whole circle less a 90° segment, or as a 3/4 circle with a right triangle added. The formula for the segment area is that of a sector less the triangle, so the computation is the same either way.
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<h3>3/4 circle area</h3>
The area of a circle is given by ...
A = πr²
so 3/4 of a circle is 3/4 this value:
3/4 circle area = (3/4)(π)(10²) = 75π . . . . square units
<h3>Triangle area</h3>
The area of the isosceles right triangle is given by ...
A = 1/2s²
A = 1/2(10²) = 50 . . . . square units
<h3>Shaded area</h3>
The shaded area is the sum of these two ...
shaded area = 3/4 circle area + right triangle area
shaded area = 75π + 50 ≈ 285.6 . . . . square units