Instantaneous rate of change = S'(r) = 8πr
S'(8) = 8π(8) = 64π
Therefore, the instantaneoud rate of change of the <span>surface area with respect to the radius r at r = 8</span> is 64π
Answer:
The answer is x>25/46
Step-by-step explanation:
Distribute 23 through the parentheses
138x-69>6
Move constant to the the right and change the sign. 138x>6+69.
Add the numbers like this: 138x>75
Divide both sides and you'll will get x>25/46 which is your answer. Let me know if this helps
Answer:
67 people i believe. I am not 100% sure..
Step-by-step explanation:
Answer B
Why is because Box B is near the 8 and goes on while Box A only is near 8 and stops there
Answer:
Step-by-step explanation:
x + 6 I x³ + 2x² - 10x + 84 I x² - 4x + 14
x³ + 6x²
<u> - - </u>
-4x² - 10x
-4x² - 24x
<u> + + </u>
14x + 84
14x + 84
<u> - - </u>
0
P(x) =(x +6)* ( x² - 4x + 14) + 0
