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LenKa [72]
3 years ago
14

1. A manufacturer of a printer determines that the mean number of days before a cartridge runs out of ink is 75 days, with a sta

ndard deviation of 6 days. Assuming a normal distribution, what is the probability that the number of days will be less than 67.5 days?
Mathematics
1 answer:
satela [25.4K]3 years ago
8 0

Answer:

P(X

And we can find this probability using the normal standard table or excel:

P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the number of days before cartridge runs out of a population, and for this case we know the distribution for X is given by:

X \sim N(75,6)  

Where \mu=75 and \sigma=6

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table or excel:

P(z

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Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0
Arada [10]

Answer:

b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0

Step-by-step explanation:

The given matrix addition is

B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

We need to find the elements of matrix B.

Let B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}

Substitute the value of matrix.

\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

After addition of two matrix we get

\begin{bmatrix}b_{11}+15&b_{12}-7&b_{13}+4\\ b_{21}+0&b_{22}+1&b_{23}+2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}

On equating both sides.

b_{11}+15=1\Rightarrow b_{11}=-14

b_{12}-7=2\Rightarrow b_{12}=9

b_{13}+4=12\Rightarrow b_{13}=8

b_{21}+0=4\Rightarrow b_{21}=4

b_{22}+1=0\Rightarrow b_{22}=-1

b_{23}+2=2\Rightarrow b_{23}=0

Therefore, the elements of matrix B are b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0.

3 0
3 years ago
The perimeter of the kitchen is 528 inches if the width of the kitchen is 120 inches what is the length of the kitchen
butalik [34]

Answer: 144 inches.


Step-by-step explanation:

1. To solve this problem you must remember the formula for calculate the perimeter of a rectangle, which is shown below:

P=2l+2w

Where l is the lenght and w is the width.

2. You know the perimeter and the width, then you can solve for the length, as following:

P-2w=2l\\l=\frac{P-2w}{2}\\l=\frac{(528in)-(2*120in))}{2}\\l=144in



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