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77julia77 [94]
3 years ago
12

The Opposite Of The Opposite Of $800 Is $800. Is His Reasonign correct? Explain

Mathematics
1 answer:
babymother [125]3 years ago
5 0

Answer:

umm... i belive yes.

Step-by-step explanation:

this is beacuse..

800 opposite wold be -800 right

and then the opposite of -800 wold be 800

so 800 is equal to 800 cus ya

so yes i belve that this is true.

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Jason observed a large art sculpture in a local park and wanted to know its height, but the sculpture was much taller than he co
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The art sculpture was 70 inches aka 5.9feet tall and if we round it well it would be 6feet so that would be its highest piont
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Solve the equation Square root of x minus 5+ 7 = 11 for the variable. Show each step of your solution process. (10 points)
Murrr4er [49]

\sqrt{x - 5} + 7 = 11

(\sqrt{x-5}) ^{2} = (4)^{2}

|x - 5| = 16

x - 5 = +/- 16

x - 5 = 16     or     x - 5 = -16

<u>   +5</u>   <u>+5   </u>           <u>   +5 </u>    <u>+5  </u>

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3 years ago
What is 2and 2/3 divided by 4/5
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How can you write a linear function in the form y=mx + b by using the two points given below (0,-2), (2,6)
elixir [45]

Answer:

y = 4x - 2

Step-by-step explanation:

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When a bactericide is added to a nutrient broth in which bacteria are​ growing, the bacteria population continues to grow for a​
baherus [9]

Answer:

a)  1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t​ is given by:

b(t) = 9^6 + 6^4t-6^3t^2

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\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t

a) Growth rates at t = 0 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}

b) Growth rates at t = 3 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}

c) Growth rates at t = 6 hours

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4 years ago
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