Answer:
b = 6i then a = -6i
b = -6i then a = 6i
Step-by-step explanation:
a+b=0
ab=36
a = -b
a(b) = 36
-b * b = 36
- b^2 = 36
b^2 = -36
Take the square root of each side
sqrt(b^2) = sqrt(-36)
b =± 6i
a = - (± 6i)
so b = 6i then a = -6i
b = -6i then a = 6i
Answer:
D. 1/5^15
Step-by-step explanation:
When an exponent is negative you need to get the reciprocal to make it positive.
Answer:
Step-by-step explanation:
jack is correct
Answer:
<h2><em><u>2a</u></em></h2>
Step-by-step explanation:
(a+b-c)-(b-a-c)
= a + b - c - b + a + c
= a + a + b - b - c + c
= <em><u>2a (Ans)</u></em>
Answer:
A: This polynomial has a degree of 2 , so the equation 12x2+5x−2=0 has two or fewer roots.
B: The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots.
Step-by-step explanation:
f(x) = 12x^2 + 5x - 2.
Since this is a quadratic equation, or a polynomial of second degree, one can easily conclude that this equation will have at most 2 roots. At most 2 roots mean that the function can have either 2 roots at maximum or less than 2 roots. Therefore, in the A category, 2nd option is the correct answer (This polynomial has a degree of 2 , so the equation 12x^2 + 5x − 2 = 0 has two or fewer roots).
To find the roots of f(x), set f(x) = 0. Therefore:
12x^2 + 5x - 2 = 0. Solving the question using the mid term breaking method shows that 12*2=24. The factors of 24 whose difference is 5 are 8 and 3. Therefore:
12x^2 + 8x - 3x - 2 = 0.
4x(3x + 2) -1(3x+2) = 0.
(4x-1)(3x+2) = 0.
4x-1 = 0 or 3x+2 = 0.
x = 1/4 or x = -2/3.
It can be seen that f(x) has two distinct real roots. Therefore, in the B category, 1st Option is the correct answer (The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots)!!!
