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kupik [55]
3 years ago
8

Lesson 1 math 6th grade Ratio problems

Mathematics
2 answers:
svp [43]3 years ago
7 0

Please show me the problems thanks

Naddika [18.5K]3 years ago
4 0
Oh those were fun am I right or were those really easy sorry I can’t help but what do you need help with
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Mai biked 6\frac{3}{4} miles today, and Noah biked 4\frac{1}{2} miles.
Alinara [238K]

It was 1.5 times the length of Noah's bike ride as Mai’s bike ride.

The problem we dealing with is related to mixed numbers which are referred to as mixed numbers and could be the whole number, and a proper division spoke together. It for the most part speaks to a number between any two whole numbers.

Since we are providing mai's rate which is  6 3/4  miles and Noah's  rate of 4 1/2 miles, So in  order to find the time the length of Noah's ride is compared to Mal's, we just need to divide the given rates by each other

=> 6 3/4 divided by 4 1/2,  

=> 27/4 divided by 9/2, (The result is an improper fractions)

=> 27/4 X 2/9

=>3/2

=> 1.5

To know more about mixed numbers refer to the link  brainly.com/question/24137171?referrer=searchResults.

#SPJ1

3 0
1 year ago
Given a function <img src="https://tex.z-dn.net/?f=f%28x%29%3D3x%5E4-5x%5E2%2B2x-3" id="TexFormula1" title="f(x)=3x^4-5x^2+2x-3"
Levart [38]

Answer:

\huge\boxed{f(-1) = -7}

Step-by-step explanation:

In order to solve for this function, we need to substitute in our value of x inside to find f(x). Since we are trying to evalue f(-1), we will substitute -1 in as x to our equation.

f(-1) = 3(-1)^4 - 5(-1)^2 + 2(-1) - 3

Now we can solve for the function by multiplying/subtracting/adding our known values.

Starting with the first term to the last term:

  • 3(-1)^4 = 3

<u><em>WAIT</em></u><em>!</em><em> How is this possible? </em>-1^4 = -1 (according to my calculator), and 3 \cdot -1 = -3, not 3!

It's important to note that taking a power of a negative number and multiplying a negative number are two different things. Let's use -2^2 as an example.

What your calculator did was follow BEMDAS since it wasn't explicitly told not to.

BEMDAS:

- Brackets

- Exponents

- Multiplication/Division

- Addition/Subtraction

Examining the equation, your calculator used this rule properly. Note that exponents come over multiplication.

So rather than  being <em>"-2 squared"</em> - it's <em>"the negative of of 2 squared."</em>

Tying this back into our problem, the squared method would only be true if it looks like -1^4. However, since we're substituting in -1, it looks like (-1)^4, so the expression reads out as "<u><em>-1 to the fourth.</em></u>"

MULTIPLYING -1 by itself 4 times results in -1\cdot-1\cdot-1\cdot-1=1.

Applying this logic to our original term, 3(-1)^4:

  • 3(-1\cdot-1\cdot-1\cdot-1)
  • 3(1)
  • 3

Therefore, our first term is 3.

Let's move on to our second and third terms.

Second term: -5x^2

  • -5(-1)^2

Applying the same logic from our first term:

  • -5(-1 \cdot -1)
  • -5(1)
  • -5

Third term: 2x

  • 2(-1) = -2

-3 is just -3, no influence of x.

Combining our terms, we have 3-5-2-3.

This comes out to be -7, hence, the value of f(-1) for our function f(x)=3x^4-5x^2+2x-3 is <u>-7</u>.

Hope this helped!

4 0
3 years ago
Read 2 more answers
Regina left the coffee shop traveling 9 mph. Then, 3 hours later, Janai left traveling the same direction at
damaskus [11]

Answer:

<em>suwi6q74diyer7ityw7reuDjuss36audlsgo74wridoyaurslhjsgjfaufalakateUd</em>

Step-by-step explanation:

will3urafg-"7'-"/-()4<u> </u><u>mhl374</u><u>y</u><u>3</u><u>l</u><u>u</u><u>s</u><u>d</u><u>u</u><u>s</u><u>i</u><u>t</u><u>z</u><u>l</u><u>a</u><u>7</u><u>w</u><u>h</u><u>f</u><u>z</u><u>s</u><u>p</u><u>r</u><u>X</u><u>j</u><u>a</u><u>u</u><u>e</u><u>g</u><u>k</u><u>z</u><u>h</u><u>r</u><u>o</u><u>y</u>

5 0
2 years ago
Each table below lists the squared residuals for a line of fit for a certain set of data points. Find the sum of the squared res
viva [34]

Answer:

c

Step-by-step explanation:

7 0
3 years ago
2xsquare+12x+19<br> Find the minimum value of f (x)
Arturiano [62]
Converting to vertex form is one way of doing this
2x^2 + 12x + 19 
= 2(x^2 + 6x) + 19
= 2 [ x + 3)^2  - 9] + 19
=  2(x + 3)^2  - 18 + 19
= 2(x + 3)^2 + 1

the minimum value is 1
5 0
3 years ago
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