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3 years ago

What is the answer to 5 + 7x – (2x + 3)

Mathematics

1 answer:

VikaD [51]3 years ago

3 0

Answer:

2+5x?

Step-by-step explanation:

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Which expression is equivalent to

Maksim231197 [3]

Answer:

Step-by-step explanation:

3 0

3 years ago

At a local grocery store, apples cost $0.50 each and bananas cost $0.30 each.

-BARSIC- [3]

1.X represents the number of apples, the y represents the number of bananas.

3. 0.50 represents the price of apples and 0.30 represents the price of bananas.

3 0

3 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

Please someone help quickly thank you very much

Tema [17]

Answer:

I think the answer is 81.

Step-by-step explanation:

Vertical angles are congruent.

x + 3 = 84

- 3 = -3

--------------

x = 81

3 0

3 years ago

What is the slope-intercept form for (1,6) and (2,5)

patriot [66]

$\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{6})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{5}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-6}{2-1}\implies \cfrac{-1}{1}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-6=-1(x-1) \\\\\\ y-6=-x+1\implies y=-x+7$

5 0

3 years ago