All categories

3 years ago

All whole numbers are rational numbers.

Mathematics

1 answer:

goldenfox [79]3 years ago

4 0

All whole numbers are rational numbers

This is always TRUE

A rational number is any number that can be expressed as the quotient or fraction. So any whole numbers can be expressed as fraction (example 3 = 3/1 or 10 = 10/1, etc...)

You might be interested in

Which is a solution to (x - 2)(x + 10) = 13 ?

stiv31 [10]

The answer is:
x=3,-11

4 0

3 years ago

Read 2 more answers

The fourth term of a sequence is 108. Each term after the first is 3 times the previous term. Write an explicit expression that

marishachu [46]

Answer:

$f(n)=4(3)^{n-1}$

Step-by-step explanation:

Let the first term be $x$ , then the terms of the sequence are:

$x,3x,9x,27x,81x,...$ .

Since the fourth term is 108, we have

$27x=108$

$\implies x=4$

Hence the sequence becomes:

$4,12,36,108,324,...$ .

The explicit expression for a geometric expression is given by:

$f(n)=ar^{n-1}$

where a=4 and r=3

The required formula is:

$f(n)=4(3)^{n-1}$

8 0

2 years ago

Referring to triangle ABC, find the area of the triangle.

ExtremeBDS [4]

Answer: area of triangle = 13.4 ft ( after rounding the answer to 3 significance figures)

Step-by-step explanation:

formula for the area of triangle

= S + S + S

= 4.34 + 3.78 + 5.27

= 13.9 ft

= 13.4 ( after rounding off to three significant figures )

5 0

3 years ago

A committee must be formed with 5 teachers and 4 students. If there are 6 teachers to choose from, and 15 students, how many dif

ZanzabumX [31]

Answer:

8190 ways

Step-by-step explanation:

Given

$Teachers = 6$

$Students = 15$

Selection

$Students = 4$

$Teachers = 5$

Required

Number of ways of selection

4 students can be selected from 15 students in:

$Students= ^{15}C_4$

Similarly.

5 teachers can be selected from 6 teachers in:

$Teachers= ^{6}C_5$

So, the required number of selection is:

$Selection = ^{15}C_4 * ^6C_5$

Apply combination formula:

$Selection = \frac{15!}{(15-4)!4!} * \frac{6!}{(6-5)!5!}$

$Selection = \frac{15!}{11!4!} * \frac{6!}{1!5!}$

$Selection = \frac{15*14*13*12*11!}{11!*4*3*2*1} * \frac{6*5!}{1*5!}$

$Selection = \frac{15*14*13*12}{4*3*2*1} * \frac{6}{1}$

$Selection = \frac{32760}{24} * 6$

$Selection = 1365 * 6$

$Selection = 8190$

8 0

2 years ago

Write an expression for the missing value in

Snowcat [4.5K]

C. a + 3

10 + 3 = 13
11 + 3 = 14
12 + 3 = 15
a + 3 = ?

5 0

3 years ago

Read 2 more answers