3 years ago

J^2 over 2j times 2j over 3g

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

Answer:

Step-by-step explanation:

given $\frac{j^2}{2j}$ × $\frac{2j}{3g}$

the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as

= $\frac{j^2}{3g}$ → D

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10 points + brainliest to first correect answer :) incorrect answers/ answers with no effort will be deleted this is easy im jus

andreev551 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Write a set of data with six values that has a mean of 28, median of 29, and a range of 18

Basile [38]

Mean is average example
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3 years ago

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a_sh-v [17]

Answer:

Step-by-step explanation:

remember PEMDAS

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now we have a mini PEMDAS situation within the parentheses: multiplication comes before addition/subtraction, so multiply -2*2 = -4, so now your equation looks like this: $\frac{80}{(6-4)}$

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3 years ago

To find 27x9 I find 27x10 and remove 1 group of 27

solniwko [45]

Answer:

yes because 10 groups 27 taking 1 group of 27 is now 9 groups of 27

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