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Ipatiy [6.2K]
3 years ago
6

J^2 over 2j times 2j over 3g

Mathematics
1 answer:
Serhud [2]3 years ago
5 0

Answer:

D

Step-by-step explanation:

given \frac{j^2}{2j} × \frac{2j}{3g}

the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as

= \frac{j^2}{3g} → D


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