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3 years ago

J^2 over 2j times 2j over 3g

Mathematics

1 answer:

Serhud [2]3 years ago

5 0

Answer:

Step-by-step explanation:

given $\frac{j^2}{2j}$ × $\frac{2j}{3g}$

the 2j on the denominator of the first fraction cancels with the 2j on the numerator of the second fraction, leaving the expression in simplified form as

= $\frac{j^2}{3g}$ → D

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3 years ago

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Answer:

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3 years ago

Read 2 more answers

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4 years ago

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Find the area of all six rectangular faces of the prism. (A= l x b)

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3 years ago