Answer:
42/90
Step-by-step explanation:
First name your decimal
times both sides by how many recurring numbers there are (in thus case the 6 has a dot on the top so it means that the six is recurring)
Subtract the one you multiplied by the one you named
make x the subject
make the fraction have no decimals and that's your final answer
It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
Answer:
Solving for we got
and replacing this we got:
And then the best option for this case would be:
b.csc x
Step-by-step explanation:
For this case we have the following expression given:
We know from math properties that the definition for cot is
If we use this definition we got:
Now we can use the following identity:
Solving for we got
and replacing this we got:
And then the best option for this case would be:
b.csc x