Answer:
Step-by-step explanation:
P(55)=(P21) +P(36)-P(55)
The ratios of the sides
hypotnuse=2x
x=short leg (oposite 30)
x√3=long leg (oposite 60)
long leg=x√3
to find x, divide by √3
longleg/√3=short leg=x
rationalize denomenator, times √3/√3
(longleg√3)/3=short leg
the legnth of the short leg is
(longleg√3)/3
The fraction of the fence completed in one hour at a rate of
of the
fence in
hours is
.
<h3>How can the fraction completed in one hour be found?</h3>
The fraction of the fence completed in
of an hour = 
Required:
The fraction of the fence the student completes per hour;
Solution;
The time
of the fence is completed =
of an hour
Therefore;

The fraction of the fence completed per hour = 
Learn more about fractions here:
brainly.com/question/21339546
1. (a) The orbital period can be calculated using the equation
T = 2πrr r
gR2
e
where r = Re + h
where re = 6378 km is the earth’s radius, r is the satellites distance
from the earth’s center and h = 205 km is the satellite’s orbital altitude, and g = 9.81m/s2
is the gravitational acceleration. With these
given values the orbital period is
Torbit = 5312.5s = 1.4757h