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castortr0y [4]
3 years ago
7

HELP PLEASE!!!!!!! This is due tomorrow. 20 points for this.

Mathematics
1 answer:
gogolik [260]3 years ago
5 0

Answer:

x=16.75 y=4.5

Step-by-step explanation:

first turn the first trapezoid sideways so the side that says 8 matches with the side that says 10. This is the proportion. 8:10. The bottom of the first trapezoid says x+2. This matches with the side that says 15. Because the side that says 15 is on the bigger trapezoid, multiply by ten. Then multiply the other trapezoid by 8. We get an equation that looks like. 8x+16=150 Simplify and 8x=134 divide and we get x=16.75. Do the same for the side with y. 8y-24=50. 8y=36 y=4.5. There you have it.

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Write 50 as a product of primes. Use index notation when giving your answer.
beks73 [17]

Answer:

2 x 5 x 5 or 2 x 5 2

Step-by-step explanation:

Prime factorization of 50 is 2 x 5 x 5 or 2 x 5 2 Prime

Hope it helps :)

pls mark brainliest :P

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1 year ago
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Can someone help me with a series of questions?
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Write the slope intercept form for the equation 2x + y =12?<br> Your answer
777dan777 [17]

Answer:

y= -2x + 12

Step-by-step explanation:

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4 0
3 years ago
Can someone please help me on e and f i dont understand it and pls explain
Lemur [1.5K]
For parts A, B, C, and D you most likely created a line. What question E is asking is for you to create a line that is perpendicular to the line you already created that also passes through the point (1,1). What is important to understand here is that the slope of the perpendicular line is the negative reciprocal of the original line's slope... if the original slope is (-4/3) than the perpendicular slope is (3/4)... then you should just plug that new slope into point-slope form or slope-intercept form to get your equation... y-y1 = m(x-x1) ... y-1= (3/4)(x-1) ... so it would be y=(3/4)x + 1/4 then for part f just convert into standard form which is just manipulating the variables... look up standard form equation on Google and manipulate the variables from there.
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3 years ago
Find the equation of the tangent line to the curve y = 2sinx at the point (pi/6,1). The equation of this tangent line can be wri
mixas84 [53]
Y = mx + b

1) m = slope of the tangent line = derivative at the point (pi/6, 1)

Function: y = 2sinx

Derivative: y ' = 2cosx

evaluate at x = pi/6=> y ' = 2cos(pi/6) = √3

2) equation using the slope and the point (pi/6, 1)

y - 1 = √3 ( x - pi/6 )

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y = √3 x + 0.093

m = √3, b = 0.093
8 0
3 years ago
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