Use gradient formula, rise over run.
y2-y1/x2-x1
Answer: 
<u>Step-by-step explanation:</u>
Note the following identities: tan² x = sec²x - 1
tan² x + sec x = 1
(sec² x -1) + sec x = 1
sec² x + sec x - 2 = 0
(sec x + 2)(sec x - 1) = 0
sec x + 2 = 0 sec x - 1 = 0
sec x = -2 sec x = 1
For the answer to the question above asking to f<span>ind the coordinates of Z without using any new variables.
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Vector WZ equals vector VP, which is (p, -q)
So Z is (-p - r + p, q - q) which is (-r, 0)
I hope my answer helped you.
Problem:
The area of the patio of a relative's house is 20 square meters.
The width of the patio is 2 meters.
What is the length of the patio?
Solution:
The area is:
A = (w) * (l)
Where,
w: width
l: long
Clearing l we have:
l = A / w
Substituting values:
l = 20/2
l = 10 meters
$25 - $4 = $21
You spent $21 on 3 boxes of granola bars.
3 boxes = $21
1 box = $21 ÷ 3 = $7
One box of granola bar costs $7.
