Answer:
add, subtract, multiply and divide complex numbers much as we would expect. We add and subtract
complex numbers by adding their real and imaginary parts:-
(a + bi)+(c + di)=(a + c)+(b + d)i,
(a + bi) − (c + di)=(a − c)+(b − d)i.
We can multiply complex numbers by expanding the brackets in the usual fashion and using i
2 = −1,
(a + bi) (c + di) = ac + bci + adi + bdi2 = (ac − bd)+(ad + bc)i,
and to divide complex numbers we note firstly that (c + di) (c − di) = c2 + d2 is real. So
a + bi
c + di = a + bi
c + di ×
c − di
c − di =
µac + bd
c2 + d2
¶
+
µbc − ad
c2 + d2
¶
i.
The number c−di which we just used, as relating to c+di, has a spec
Answer:
114
Step-by-step explanation:
that's supplementary
Answer:
every 2 years
Step-by-step explanation:
since it is t/2 for the exponent - thas the answer on khan
Answer:
2.
x=3 y=3
Step-by-step explanation:
3-3=0
3+3=6
If 3x-3y equals 0, then what's x+y. It concluded to 6
x=6 , y = 4
Step-by-step explanation:
( x-2,6)=(4,Y+2)
this means; (x-2) &( 4) stands for" x "axis.
and( 6 )& (y+2) stands for y axis.
So, we can say( x-2)=X1 & (4)=X2 , (6)=Y1 & (y+2)=Y2
then; to Solve The Equation we use The Formula: X1=X2 for "X" And Y1=Y2 for "Y".
Solution: for "X" ; X1=X2
x-2= 4
x=4+2
x=<u>6</u>
For "Y" ; Y1=Y2
6 = y+2
y=6-2
y=<u>4</u>
finally check ; ( (x-2),6) = (4,(y+2) )
(6-2),6 = (4,(4+2) )
( (4),6) = (4,(6) )
(4,6) = (4,6)
so, X1 =X2 ; 4 = 4
Y1 = Y2 ; 6 = 6
