3 years ago

Find the value of y.

1 answer:

5 0

$y^2 = 9(3+9)\\\\y^2 = 3^2\cdot3\cdot2^2\\\\y = 6\sqrt{3}$

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Andrews [41]

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AlexFokin [52]

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2 years ago

Darya [45]

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Sonbull [250]

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kiruha [24]

Answer:

we have:

$v = \frac{1}{3} \pi \: r {}^{2}h \\ \\ = > 60\pi = \frac{1}{3} \pi \: r {}^{2} h \\ \\ < = > 180 = r {}^{2} h$

=> r²h = 10.18 = 9.20 = 5.36 = 6.30 = 4.45 = 12.15

=> only r²h = 5.36 satisfy the problem

=> h = 5

h = 5 r = 6

h = 5 r = 6=> d = 12

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2 years ago