Question

Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x h(g(f(x)))

Answer 1

Answer:

h[g{f(x)}] = -(8x² + 40x + 50) is the answer.

Step-by-step explanation:

The given functions are f(x) = 2x + 5 , g(x) = x² and h(x) = -2x.

We have to find the value of h[g{f(x)}]

To get the value we will find the value of g{f(x)} first.

g{f(x)} = (2x + 5)²= 4x²+ 25 + 20x

Then we will find the value of h[g{f(x)}]

h[g{f(x)}] =  -2(4x²+ 20x + 25) = (-8x² - 40x -50)

So the answer is h[g{f(x)}] = -(8x² + 40x + 50)

Answer 2

Answer:

h(g(f(x)))=  -8x²-40x-50

Step-by-step explanation:

We have given three function.

f(x) = 2x + 5 and g(x) = x² and h(x) = -2x

we have to find h(g(f(x))).

h(g(f(x)))  = ?

Putting value , we have

h(g(f(x)))  = h(g(2x+5)

h(g(f(x)))  = h((2x+5)²)

h(g(f(x)))  =  h(4x²+20x+25)

h(g(f(x)))  =  -2(4x²+20x+25)

h(g(f(x)))  =  -8x²-40x-50 which is the answer.