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3 years ago

Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x h(g(f(x)))

Mathematics

2 answers:

defon3 years ago

4 0

Answer:

h[g{f(x)}] = -(8x² + 40x + 50) is the answer.

Step-by-step explanation:

The given functions are f(x) = 2x + 5 , g(x) = x² and h(x) = -2x.

We have to find the value of h[g{f(x)}]

To get the value we will find the value of g{f(x)} first.

g{f(x)} = (2x + 5)²= 4x²+ 25 + 20x

Then we will find the value of h[g{f(x)}]

h[g{f(x)}] = -2(4x²+ 20x + 25) = (-8x² - 40x -50)

So the answer is h[g{f(x)}] = -(8x² + 40x + 50)

Vinvika [58]3 years ago

3 0

Answer:

h(g(f(x)))= -8x²-40x-50

Step-by-step explanation:

We have given three function.

f(x) = 2x + 5 and g(x) = x² and h(x) = -2x

we have to find h(g(f(x))).

h(g(f(x))) = ?

Putting value , we have

h(g(f(x))) = h(g(2x+5)

h(g(f(x))) = h((2x+5)²)

h(g(f(x))) = h(4x²+20x+25)

h(g(f(x))) = -2(4x²+20x+25)

h(g(f(x))) = -8x²-40x-50 which is the answer.

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Step-by-step explanation:

If you multiply the x and y points of A, (-3,-3), by 1/3 then you find: (-1,-1).

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3 years ago

It costs Sally 20 cents to make a cup of lemonade, and she sells each cup for 50 cents. She is using the following identity to c

mote1985 [20]

She would make 3.00 dollars

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3 years ago

Factor completely:<br><br> 7r^2− 64r + 64

poizon [28]

Answer:

7r^2-64r+64

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Step-by-step explanation:

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2 years ago

joe has a handful of dimes and quarters that values to $5.30. He has one fewer than twice as many dimes than quarters. How many

OlgaM077 [116]

Answer:

12 quarters 23 dimes

Step-by-step explanation:

x(0.25)+(2x-1)(0.10)=5.30

0.25x+0.2x-0.10=5.30

0.45x=5.40

x=12

12 quarters

12(2)=24-1=23 dimes

5 0

2 years ago

In a soccer game the winner gains 3 points, while the loser gains 0 points. If the game is a draw, then the two teams gain 1 poi

Mariana [72]

Answer:

10 losses

Step-by-step explanation:

Here, we want to get the greatest possible number of games the team lost

Let the number of games won be x

Number drawn be y

Number lost be z

Mathematically;

x + y + z = 38

Let’s now work with the points

3(x) + 1(y) + z(0) = 80

3x + y = 80

So we have two equations here;

x + y + z = 80

3x + y = 80

The greatest possible number of games lost will minimize both the number of games won and the number of games drawn

We can have the following possible combinations of draws and wins;

26-2

25-5

24-8

23-11

22-14

21-17

21-17 is the highest possible to give a loss of zero

Subtracting each sum from 38, we have the following loses:

10, 8, 6, 4, 2 and 0

This shows the greatest possible number of games lost is 10

5 0

2 years ago