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4 years ago

Given: f(x) = 2x + 5 and g(x) = x2 and h(x) = -2x h(g(f(x)))

Mathematics

2 answers:

defon4 years ago

4 0

Answer:

h[g{f(x)}] = -(8x² + 40x + 50) is the answer.

Step-by-step explanation:

The given functions are f(x) = 2x + 5 , g(x) = x² and h(x) = -2x.

We have to find the value of h[g{f(x)}]

To get the value we will find the value of g{f(x)} first.

g{f(x)} = (2x + 5)²= 4x²+ 25 + 20x

Then we will find the value of h[g{f(x)}]

h[g{f(x)}] = -2(4x²+ 20x + 25) = (-8x² - 40x -50)

So the answer is h[g{f(x)}] = -(8x² + 40x + 50)

Vinvika [58]4 years ago

3 0

Answer:

h(g(f(x)))= -8x²-40x-50

Step-by-step explanation:

We have given three function.

f(x) = 2x + 5 and g(x) = x² and h(x) = -2x

we have to find h(g(f(x))).

h(g(f(x))) = ?

Putting value , we have

h(g(f(x))) = h(g(2x+5)

h(g(f(x))) = h((2x+5)²)

h(g(f(x))) = h(4x²+20x+25)

h(g(f(x))) = -2(4x²+20x+25)

h(g(f(x))) = -8x²-40x-50 which is the answer.

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