There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
Find a number that both of the denominates make the same number for example if one denominator is 1/7 and the other is 2/6 then you
2/6 * 7 = 14 over 42 then the other one would be 1/7 *6 which would be 6 over 42 you find common denominators by finding a number both of the bottom ones can equal. hope this helps
So, by multiplying the exponents, you would add all of the square roots together. For example for your question you would add 1+1+4+5=11 so the answer is c to the power of 11
Answer:
-7.2
Step-by-step explanation:
-4(0.3)-6
-1.2-6
-7.2
Greetings!Simplify the Expression.
Distribute the Parenthesis.
<em>How?</em><span> Multiply the terms inside the Parenthesis by the term outside of the Parenthesis.
</span>
Combine Like Terms.
The Answer Is:
![\left[\begin{array}{ccc}17\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D17%5Cend%7Barray%7D%5Cright%5D%20)
Hope this helps.
-Benjamin
