Answer:
Option D In step 4 Keith should have subtracted 5 from each side
Step-by-step explanation:
step 1
we have
f(x)=7x+5 -----> given
step 1 is correct
step 2
Change f(x) to y
y=7x+5
so
step 2 is correct
step 3
Exchange x for y and y for x
x=7y+5
so
step 3 is correct
step 4
Subtract 5 each side
x-5=7y+5-5
x-5=7y
<u><em>step 4 is not correct</em></u>
step 5
Divide by 7 each side
(x-5)/7=y
step 6
Change y to g(x)
(x-5)/7=g(x)
step 7
switch sides of the equation
g(x)=(x-5)/7
therefore
In step 4 Keith should have subtracted 5 from each side
Answer:
There are no common divisors
Step-by-step explanation:
20)
using
<span>a^3 + b^3 = (a+b)(a^2 − ab + b^2)
</span>so
w^3 + 125z^3
= w^3 +(5z)^3
= (w + 5z)(w^2 - 5wz + 25z^2)
hope it helps
