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grin007 [14]
3 years ago
6

Jim’s Gym had income of $20,350 last month.The total increased by $2,000 this month.What was the percent increase to the nearest

percent?
Mathematics
1 answer:
frozen [14]3 years ago
6 0

Answer:

10%

Step-by-step explanation:

To find the percentage, ask yourself, how much is 2000 of the original value which is 20350.   This can be solved by the following equation.

2000/20350=

The answer is approximately 0.09828.   Then, convert this to a percent. 9.828%. Then, round it to the nearest percent. The answer is 10%

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5 0
2 years ago
F(x)=x^2+5x what are the real zeroes of this function?
Marina CMI [18]

Answer:

0, -5

Step-by-step explanation:

5 0
2 years ago
Which of the following expressions is equivalent to 14xy – 28x – 36y + 48? 2(7x – 6)(y – 2)(3y + 4) 2(7x – 6)(y – 2)(3y – 4) 2[7
Zolol [24]

The expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

<h3>Factorizing expressions</h3>

Factorization is a way of separating the equations into two separate factors.

Given the expression below;

14xy – 28x – 36y + 48

Group

(14xy – 28x) – (36y + 48)

14x(y - 2) - 12(3y-4)

Factor out the value of 2 from both terms

2[7x(y-2)-6(3y-4)]

Hence the expression that is equivalent to 14xy – 28x – 36y + 48 is 2[7x(y-2)-6(3y-4)]

Learn more on factorization here: brainly.com/question/25829061

#SPJ1

7 0
2 years ago
I need help please help me :(
Studentka2010 [4]

Answer:

IM SUCH AN INFLUENCER :D

Step-by-step explanation:

5 0
2 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
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