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Rufina [12.5K]
4 years ago
7

An article reports "attendance dropped 2% this year, to 5053." What was the attendance before the drop? (Round your answer to th

e nearest whole number.)
Mathematics
1 answer:
Shalnov [3]4 years ago
8 0

Answer:

5156

Step-by-step explanation:

Let x represent the initial attendance;

Since the initial attendance dropped by 2%

New attendance = x - 2% of x = x - 0.02x

New attendance = 0.98x

Given;

New attendance = 5053

Equating the values and solving for x;

0.98x = 5053

x = 5053/0.98

x = 5156.12

x = 5156

Initial attendance before the drop = 5156

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Question 3 This questions requires you to examine computational differences for methods used to calculate sample variation. You
Licemer1 [7]

Answer:

sigma formulas are executed by using for loop to sum all the values.

public class H4_Q3{

public static void main(String[] args)

{

//Part a

double[] values = {100000000.6, 99999999.8, 100000002.8, 99999998.5, 100000001.3};

int n = values.length;

//Part b;

double sum = 0;

double sample_average = 0;

double sample_variance = 0;

int i = 0;

for(i = 0; i < n; i++)

{

sum = sum + values[i];

}

sample_average = sum/n;

for(i = 0; i < n; i++)

{

sample_variance = sample_variance + (Math.sqrt(values[i]) - sample_average);

}

System.out.println("Sample variance (Part b formula): "+sample_variance);

//Part c

double sum_squared = 0;

double sum_values = sample_average;

for(i = 0; i < n; i++)

{

sum_squared = sum_squared + Math.sqrt(values[i]);

}

sum_squared = sum_squared/n;

sample_variance = (sum_squared - Math.sqrt(sum_values)) * (n/ (n - 1));

System.out.println("Sample variance (Part c formula): "+sample_variance);

//Part d

sample_variance = 0;

double[] M = new double[n];

double[] S = new double[n];

M[0] = values[0];

S[0] = 0;

i = 1;

while(i < n)

{

M[i] = M[i-1] + ((values[i] - M[i-1])/i+1);

S[i] = S[i-1] + (values[i] - M[i-1]) * (values[i] - M[i]);

i++;

}

System.out.println("Sample variance (Part d formula): "+S[n-1]/n);

}

}

8 0
4 years ago
HELP PLEASE!!!!!!!!!
Luba_88 [7]

Answer:

z

Step-by-step explanatio you got this bro

7 0
4 years ago
Factor the expression P^4+3p^3-10p^2
bonufazy [111]

Answer:

p^2(p+5)(p-2)

Step-by-step explanation:

To begin factoring the expression p^4+3p^3-10p^2, we use the GCF or greatest common factor. The greatest common factor is the greatest number that will divide into two or more values. We start to find it by factoring each term:

p^4=p*p*p*p

3p^3: 3*p*p*p

-10p^2: -10*p*p

Remember -10 can factor into smaller numbers but since it doesn't have common factors with the others, we've chosen to leave it as -10.

We notice the only common factors bare p*p or p^2.

We write in the form p^2(____+_____+_____). We find the inside of the parenthesis by dividing each term by p^2.

\frac{p^4}{p^2} =p^2

\frac{3p^3}{p^2} =3p

\frac{-10p^2}{p^2}=-10

p^2(p^2+3p-10).

We are not finished yet. We have a trinomial (3 terms) which also factors. We factor by splitting the middle term 3p into factors of -10 which add to 3.

--10 = 5 * -2

3p= 5p +-2p

We write p^2(p+5)(p-2).


5 0
4 years ago
I NEED ANSWER ASAP. Sorry for my hand reflection.. XD
VashaNatasha [74]
Eeehhhhhhh

1, 3, 1, 0, 0, 1, 0, 0, 1, 1
5 0
4 years ago
Describe the translation. y = (x-5)squared +5 - y = (x-))squared +0
vovangra [49]

In functions; translations are used to move lines, points or shapes across the graph (i.e. up, down, right or left).

The translation from y = (x - 5)^2 +5 to y = (x - 0)^2 +0 is to shift y = (x - 5)^2 +5 to the left by 5 units and then downward by 5 units

The given parameters are:

y = (x - 5)^2 +5

y = (x - 0)^2 +0

Assume the first point is: y = (x - 5)^2 +5

While the second is: y = (x - 0)^2 +0

The first point is first shifted left by 5 units

The rule to this translation is: (x,y) \to (x + 5,y)

So, we have:

y' = (x - 5 + 5)^2 + 5

y' = (x - 0)^2 + 5

Next, the resulting function is shifted down by 5 units.

The rule to this translation is: (x,y) \to (x,y- 5)

So, we have:

y" = y' - 5

This gives:

y" = (x - 0)^2 + 5 - 5

y" = (x - 0)^2 + 0

Hence, the translation from y = (x - 5)^2 +5 to y = (x - 0)^2 +0 is to shift y = (x - 5)^2 +5 to the left by 5 units and then downward by 5 units

Read more about transformations at:

brainly.com/question/16619654

7 0
3 years ago
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