Answer:
a₁₃ = - 27x - 41
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = - 3x + 7
d = a₂ - a₁ = - 5x + 3 - (- 3x + 7)
= - 5x + 3 + 3x - 7
= - 2x - 4
Then
a₁₃ = - 3x + 7 + 12(- 2x - 4)
= - 3x + 7 - 24x - 48
= - 27x - 41
Answer:
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Step-by-step explanation:
Answer:
[12, 15]
Step-by-step explanation:
{6x + 5y = 147
{8x + 4y = 156
-¾[8x + 4y = 156]
{6x + 5y = 147
{-6x - 3y = -117 ← New Equation
________________
2y = 30
___ ___
2 2
y = 15 [Plug this back into both equations to get the x-coordinate of 12]; 12 = x
So, using the Elimination Method, what I did here was took the bottom equation and multiplied it by -¾, turning 8x to -6x, canceling out all <em>x-terms</em><em>.</em><em> </em>It does not matter which variable you choose to eliminate, as long as you know what you are doing.
I am joyous to assist you anytime.
Answer:
work is shown and pictured
Answer:
x=y=z=90.
Step-by-step explanation:
let the 3 numbers be x,y,z.
let s be sum
s=x+y+z
we need to maximize xy+yz+zx
or , xy + y(270-(x+y))+x(270-(x+y)) = P(x)
Use Lagrange's Multipliers
⇒ΔP= λΔS
⇒
⇒y=x
⇒\frac{x+z}{x+y} =1
⇒z=y
⇒x=y=z
⇒3x = 270
⇒x= 90
hence, x=y=z=90.
