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vitfil [10]
3 years ago
10

Can someone plz help me with 15-19

Mathematics
1 answer:
Leona [35]3 years ago
4 0
#15 
10-3
#16 
n/4
#17
2<span>³
#18
3/x</span><span>≥17
#19
n/6>36

Hope this helps!</span>
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Given that sin x = cos 2x find the value of x​
natali 33 [55]

Answer:

The most straightforward way to obtain the expression for cos(2x) is by using the "cosine of the sum" formula: cos(x + y) = cosx*cosy - sinx*siny. cos(2x) = cos² (x) - (1 - cos²(x)) = 2cos²(x) - 1. = 2cos²(x) - 1.

Step-by-step explanation:

7 0
2 years ago
A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) afte
Vlad1618 [11]

A quadratic equation is in the form of ax²+bx+c. The time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.

<h3>What is a quadratic equation?</h3>

A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.

The complete question is:

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 31 ft/s. The ball's height h (in feet) after 7 seconds is given by the following, h=2+31t-16t². Find all values of t for which the ball's height is  16 feet. Round your answer(s) to the nearest hundredth.

The time at which the height of the ball is 16 feet can be found by,

h = 2 + 31t - 16t²

16 = 2 + 31t - 16t²

16 - 2 - 31t + 16t² = 0

16t² - 31t + 14 = 0

t = \dfrac{-(-31)\pm \sqrt{(-31)^2-4(16)(14)}}{2(16)}\\\\

t = 0.717 , 1.221

Hence, the time at which the height of the ball is 16 feets is 0.717 seconds and 1.221 seconds.

Learn more about Quadratic Equations:

brainly.com/question/2263981

#SPJ1

4 0
2 years ago
(Please help, problem is in the photo.)
Rama09 [41]
First we need to find the gradient of K
which is y1-y2/x1-x2
(-1,3) and (5,-2)
so it becomes 3-(-2)/-1-5
m=-5/6
when two lines are perpendicular their gradients multiply to make -1
that means the gradient of L has to be 6/5
we can substitute the point on L (5,-2) and the gradient of 6/5 into y=mx+c
-2 = (6/5) x 5 + c
c = -8
the equation of line L is y= 6x/5 -8
6 0
2 years ago
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Which properties are present in a table that represents a logarithmic function in the form y=log8^(x) when b&gt;1 I. The y-value
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Answer: its C:I, III, and IV just took the test.

Step-by-step explanation:

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3 years ago
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gia is thinking of an number which she calls n she adds 4 to the number and then doubleswhat is gia's final number if her starti
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26 is the answer
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3 years ago
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