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marin [14]
3 years ago
15

Which method would i use to solve ax^2+c=d? justify your answer.

Mathematics
1 answer:
san4es73 [151]3 years ago
5 0

9514 1404 393

Answer:

  x = ±√((d -c)/a)

Step-by-step explanation:

The usual "solve for ..." approach works fine in this case.

  ax^2 +c = d

  ax^2 = d - c . . . . . subtract c

  x^2 = (d -c)/a . . . . divide by a

  x = ±√((d -c)/a) . . . take the square root

_____

When there are numbers, a graphical solution could work. It depends on whether an exact or approximate solution is required.

_____

<em>Comment on "solve for ..."</em>

When solving an equation for a specific variable, it is worthwhile to consider the Order of Operations. Look at what has been done to the variable, then undo those operations in reverse order. Here, the variable has been squared, the product multiplied by 'a', that product added to c. So, the "undo" consists of subtracting 'c', dividing by 'a', and taking the square root.

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(x²+x-6)/(x-7)≤0

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Answered by GAUTHMATH

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3 years ago
What is equivalent to 1/40
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2/80 is equivalent 
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Read 2 more answers
9 + 0 = 9 is an example of which property? A.Commutative property of addition B.Identity property of addition C.Multiplicative p
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4 0
3 years ago
Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

20y=x^2-10-15

Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

Where the vertex is

(h,k)

As we can see, h = 5 and k = -2, then the vertex is

(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

We have a = 1/20, therefore

\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

The focus is

(5,3)

And the last one, the directrix, it's

y=k-\frac{1}{4a}

Then

\begin{gathered} y=-2-5 \\  \\ y=-7 \end{gathered}

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0
1 year ago
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