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frozen [14]
3 years ago
7

Some projectors use a connection technology called _______________ that enables long-range connectivity for uncompressed HD vide

o and audio over Cat 5a or Cat 6 network cables.
Computers and Technology
1 answer:
Rzqust [24]3 years ago
5 0

Answer:

HDbaseT

Explanation:

HDbaseT is  a global connectivity standard for transmitting uncompressed high definition videos, audios, power, usb, ethernet home networking and some control signals for up to 100 meters, over a category cable like Cat 5a or Cat 6 cables.

The projector uses the HDbaseT for these reasons and for the fact that it eliminates clusters in cables without affecting its performance or high quality. This gives a high quality output display from the projector.

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Hackers often argue that hacking is for the good of all people because it points out flaws in computer systems. do you agree wit
zzz [600]
 "Hackers" who work for companies to expose security flaws are definitely good, they're helping protect systems, often referred to as "white-hat" hackers. Many companies hire people like these or offer bounties for such people who can find vulnerabilities. One could say that even without permission, people who hack with the intent of demonstrating holes in security or improving a service could be considered good.

However, I don't believe that as firstly, they are breaking the law, and secondly, they are stealing data and invading people's privacy. One might as well break into somebody's house to say their security is bad! 
6 0
4 years ago
Question # 2 Multiple Select You wrote a program to compare the portion of drivers who were on the phone. Which statements are t
3241004551 [841]

Answer: A different set of observations might result in a larger portion of male drivers being on the phone.

You could modify the program to allow the user to enter the data.

Even when confident that the mathematical calculations are correct, you still need to be careful about how you interpret the results.

It is important to test your program with a small enough set of data that you can know what the result should be.

Explanation: Got it right

4 0
3 years ago
JAVA
qwelly [4]

public class MyClass {

   public static void main(String args[]) {

     int x = 1;

     int total = 0;

     for (int i = 1; i <= 10; i++){

         x *= i;

         total += x;

     }

     System.out.println(total);

   }

}

This program finds the sum of that series to the tenth term, the sum is: 4037913. I hope this helps.

6 0
3 years ago
Consider the following code segment:
prisoha [69]

ArrayLists are arrays that can be resized

The list that represents the value of nums after executing the code segments is [20, 30, 90, 50]

<h3>How to determine the value of the list</h3>

From lines 1 to 5 of the program, the content of the nums list is:

nums = [10, 20, 30, 40, 50]

Next, the element at the 3rd index is removed and saved in x.

So, we have:

nums = [10, 20, 30, 50]

x= 40

Next, the element at the 0 index is removed and then added to x.

The result is then saved in y

So, we have:

nums = [20, 30, 50]

y= 50

x = 40

The values of x and y are added and then inserted at the 2nd index of the arraylist.

So, we have:

nums = [20, 30, 90, 50]

Hence, the list that represents the value of nums is [20, 30, 90, 50]

Read more about arraylists at:

brainly.com/question/26264399

8 0
2 years ago
The older computer had a CPU that ran at 266MHz compared to a current CPU that runs 3.7GHz. How many times faster is the new CPU
sergij07 [2.7K]

Answer:

Number of times new computer faster than old computer = 13.90 times (Approx)

Explanation:

Given:

Clock speed of old computer = 266 MHz

Clock speed of new computer = 3.7 GHz

266MHz = 0.266GHz

Find:

Number of times new computer faster than old computer

Computation:

Number of times new computer faster than old computer = Clock speed of new computer / Clock speed of old computer

Number of times new computer faster than old computer = 3.7 / 266

Number of times new computer faster than old computer = 3.7 / 0.266

Number of times new computer faster than old computer = 13.90 times (Approx)

3 0
3 years ago
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