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Mnenie [13.5K]
3 years ago
6

Simplify 2 to the fifth power over 3 squared all raised to the fourth power. 2 to the twentieth power over 3 to the eighth power

2 to the ninth power over 3 to the eigth power 8 to the fifth power over 12 squared 2 over 3 squared
Mathematics
1 answer:
Murrr4er [49]3 years ago
7 0

2 to the fifth power over 3 squared all raised to the fourth power

\left(\dfrac{2^5}{3^2}\right)^4=\dfrac{(2^5)^4}{(3^2)^4}=\dfrac{2^{5\cdot4}}{3^{2\cdot4}}=\dfrac{2^{20}}{3^8}

Answer: 2 to the twentieth power over 3 to the eighth power

Used:

\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a^n)^m=a^{n\cdot m}

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