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andreev551 [17]
3 years ago
8

Solve questions 1-10

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0
1) 3/8 is bigger because it equals 0.375
2) 5/6 is bigger because it equals 0.833 whereas 7/9 equals 0.77
3) 572.00
4) 2475.00
5) I dunno
6) I dunno
7) 300.00
8) 402.336 km
9) 6.4 miles
10) 54/5=10.8

Hope this helps! :)

ivolga24 [154]3 years ago
3 0
1. 3/8
2.5/6
3.52
4.25
5.24
6.13
7.300
8.400
9.16÷5 Anw×2
10.6×0.5555555556
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Assume that lines that appear to be tangent are tangent. O is the center of the circle. Find the value of x. (Figures are not dr
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x is 68 as the angles O and x must total 180°

4 0
3 years ago
Help me with this question
Law Incorporation [45]

greatest to least: 6.32, 6, 4.27, 4, 3.5 .

I got 4.27 by multiplying 4 x 11, adding three which makes it 47 and then divided it by 11

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3 years ago
Solving equations and Inequalities 1 ) -10p=2(p-12)
MArishka [77]
The answer is 2 = p
Explanation: Here the goal is to get the variable "p" by itself, so first your have to distribute 2 to (p-12) which gives you -10p = 2p-24. Then you add 10p on both sides so that the variable is on one side. Then you add 24 to both sides. After that you divide 12 from both sides, giving you 2 = P

-10P = 2(p-12)
-10p = 2p-24
+10p +10p
0 = 12p-24
+24 +24
24 = 12p
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2 = p
5 0
4 years ago
You buy a new video game for 59.99 the sales tax is 8% what is the total cost for the game including sales tax?
astraxan [27]
Well first of all the sales tax is 4.80 so now you add them.So 59.99 + 4.80 is 64.79.

But if you're supposed to round then you would just add 60.00 + 4.80 is 64.80.

Hope this helps :D 

If I'm wrong I'm sorry D:
5 0
3 years ago
Read 2 more answers
Sketch the region bounded by the curves x=y3,x=1, and y=0 then find the volume of the solid generated by revolving this region a
NeX [460]

According to the question, the region is bounded by the curve with the given data as x = y^{3} , x=1, y=0.

To compute the volume of the solid, use the disk method. The given object is rotated along the horizontal axis with the disk cross sectional area and the volume can be written as:

v=\int\limits^a_b {\pi x^{2} } \, dx

As per question, when x = 1 then the value of y is: y = 1

Now, substituting calculated values in the expression:

v=\int\limits^a_b {\pi x^{2} } \, dx=v=\int\limits^0_1 {\pi x^{2} } \, dx

Substitute the value of the variable 'x':

Therefore, the expression can be written as:

v=\int\limits^a_b {\pi x^{2} } \, dx=v=\int\limits^0_1 {\pi x^{2} } \, dx=\int\limits^0_1 {\pi (y^{3}) ^{2} } \, dx=\frac{\pi }{7}=0.448

To learn more about the integration from the given link:

<u>brainly.com/question/988162</u>

#SPJ4

5 0
2 years ago
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