Solve questions 1-10

Mathematics

2 answers:

erastovalidia [21]3 years ago

8 0

1) 3/8 is bigger because it equals 0.375
2) 5/6 is bigger because it equals 0.833 whereas 7/9 equals 0.77
3) 572.00
4) 2475.00
5) I dunno
6) I dunno
7) 300.00
8) 402.336 km
9) 6.4 miles
10) 54/5=10.8

Hope this helps! :)

ivolga24 [154]3 years ago

3 0

1. 3/8
2.5/6
3.52
4.25
5.24
6.13
7.300
8.400
9.16÷5 Anw×2
10.6×0.5555555556

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Ierofanga [76]

The answer of the first photo is -6/5

7 0

3 years ago

Read 2 more answers

Prove the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus. use the distance formula

riadik2000 [5.3K]

In order to prove this, we have to put the trapezoid to the coordinate system. In the attached photo you can see how it has to be put. The coordinates for the vertices of trapezoid written according to the midpoint principle. By using the distance between two points formula, we can find the coordinates for the vertices of the rhombus.
$D_{x} = \frac{-2b-2a}{2}=-b-a$ and $D_{y}= \frac{2c+0}{2}=c$ . The coordinates of D is $(-b-a, c)$
$E_{x} = \frac{-2b+2b}{2}=0$ and $E_{y}= \frac{2c+2c}{2}=2c$ . The coordinates of E is $(0,2c)$
Since we have the reflection in this graph, the coordinates of F is $(b+a, c)$
And the coordinates of G is (0,0).

Using the distance formula, we can find that
$DE= \sqrt{(-b-a)^{2}+ c^{2}}=\sqrt{(b+a)^{2} + c^{2}}$
$EF= \sqrt{(b+a)^{2} + c^{2} }$
$GF= \sqrt{(b+a )^{2} + c^{2} }$
$DG= \sqrt{(b+a)^{2}+ c^{2}$

Since all the sides are equal this completes our proof. Additionally, we can find the distances of EG and DF in order to show that the diagonals of this rhombus are not equal. So that it is not a square, but rhombus.