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Oxana [17]
3 years ago
9

Wilma buys a new game that is priced $43.89. She gets successive discounts of 15% followed by 5% off on the game. The purchase p

rice of Wilma’s game is _____ of the original price. a. 79.5% b. 80% c. 80.75% d. 82%
Mathematics
2 answers:
jek_recluse [69]3 years ago
4 0
The answer is C. 80.75%

Hope this helps!
Zielflug [23.3K]3 years ago
4 0

Answer:


Step-by-step explanation:

the correct answer is C

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What two numbers have a product of -22 and a sum of -9?
omeli [17]

Answer:

2 and -11

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I know this isn't math but, is anyone willing to answer or help me at least answer this question?
sergeinik [125]

Answer:

What happened frnd?

plz answer me!

have a great and pleasant day ahead

8 0
3 years ago
Using long division to find the quotient, what changes do you first
lora16 [44]

Answer:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

Step-by-step explanation:

Given

Dividend = 125x^3 - 8

Divisor = 5x - 2

Required

Determine the quotient

See attachment for complete process.

First, divide 125x^3 by 5x

\frac{125x^3}{5x} =25x^2

Write 25x^2 at the top

Multiply 5x - 2 by 25x^2

= 125x^3 - 50x^2

Subtract from 125x^3 - 8

i.e.

125x^3 - 8 - (125x^3 - 50x^2) = 50x^2 - 8

Step 2:

Divide 50x^2 by 5x

\frac{50x^2}{5x} = 10x

Write 10x at the top

Multiply 5x - 2 by 10x

= 50x^2 - 20x

Subtract from 50x^2 - 8

i.e.

50x^2 - 8 - (50x^2 - 20x) = 20x - 8

Step 3:

Divide 20x by 5x

\frac{20x}{5x} = 4

Write 4 at the top

Multiply 5x - 2 by 4

= 20x - 8

Subtract from 20x - 8

i.e.

20x - 8 - (20x - 8) = 0

Hence:

\frac{125x^3 - 8}{5x - 2} = 25x^2 + 10x +4

8 0
3 years ago
30 points
Debora [2.8K]
Well what is 30x3 (because that is how you would find what is one third of unknown) then you find the answer witch is 90$
7 0
3 years ago
X + 2y = 5<br> x - 3y = 7 <br> What is the value of the y-determinant? <br> -2<br> -1 <br> 2
grandymaker [24]

Answer:

y-determinant = 2

Step-by-step explanation:

Given the following system of equation:

  • x + 2y = 5
  • x - 3y = 7

Let's represent it using a matrix:

\left[\begin{array}{ccc}1&2\\1&-3\end{array}\right] = \left[\begin{array}{ccc}5\\7\end{array}\right]

The y‐numerator determinant is formed by taking the constant terms from the system and placing them in the y‐coefficient positions and retaining the x‐coefficients. Then:

\left[\begin{array}{ccc}1&5\\1&7\end{array}\right]

y-determinant = (1)(7) - (5)(1) = 2.

Therefore, the y-determinant = 2

5 0
3 years ago
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