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3 years ago

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Wilma buys a new game that is priced $43.89. She gets successive discounts of 15% followed by 5% off on the game. The purchase p

rice of Wilma’s game is _____ of the original price. a. 79.5% b. 80% c. 80.75% d. 82%

2 answers:

jek_recluse [69]3 years ago

4 0

The answer is C. 80.75%

Hope this helps!

Zielflug [23.3K]3 years ago

4 0

Answer:

Step-by-step explanation:

the correct answer is C

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Identify the quadratic term in the function, f(x)=2x^2-3x+5

Nadusha1986 [10]

Answer: 2x^2

The three terms are
2x^2
-3x
5
as they are separated by a plus sign. You can think of it as 2x^2 + (-3x) + 5 if you want. The quadratic term is the term with the exponent of 2

7 0

3 years ago

Cone A has a surface area of 384 ft2 and Cone B has a surface area of 96 ft?. What is the ratio of their volume?

ELEN [110]

Answer:

8 : 1

Step-by-step explanation:

Given ratio of sides = a : b, then

ratio of area = a² : b²

ratio of volumes = a³ : b³

Given

ratio of areas = 384 : 96 = 4 : 1 ← in simplest form, then

ratio of sides = $\sqrt{4}$ : $\sqrt{1}$ = 2 : 1

Hence

ratio of volumes = 2³ : 1³ = 8 : 1

6 0

3 years ago

Please Help me. What is the answer?

vekshin1

Answer:

-11

Step-by-step explanation:

Triangle ABC

SO,

AB = AC +BC

x + 8 = 2x -5 + (BD + DC)

x + 8 = 2x-5 + 10 +14

x + 8 = 2x + 19

2x - x = -19 + 8

x = -11

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago

A solid aluminum cube has sides each of length l . A second cube of the same material has sides four times the length of the fir

timofeeve [1]

The formula to find the volume of cube

cube = s^3

Therefore volume is equal to I^3

The second cube has 4x the First cube

4 × (I^3) = 4 ×I^3

Total volume of the second cube= 4I^3 cm3

Fact: the density(mass ÷ volume) of aluminium is 2.40g/cm3

Making mass the subject of the formula:

D = M ÷ V
(Times volume to remove deno minator)

Mass = Density × Volume

Mass = 2.40 × 4I ^3

Mass = 8.40I^3

By physics

weight= m × g

where
M = mass
g = acceleration due to gravity (= 9.8)

W = 8.40 I^3 × 9.8

Weight of aluminium = 82.32I^3

3 0

3 years ago