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Rzqust [24]
3 years ago
12

How do you do this? -x+5=10

Mathematics
1 answer:
Gennadij [26K]3 years ago
6 0
-(1)x + 5 = 10 
      -5     -5
----------------
  -x = 5
 +1  +1
----------
 x = 6
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Estimate the surface area of a cube with side length 9.9 in.
Verizon [17]
Answer:

≈ 588.06in^2

Step by step:

Formula for a cube= 6a^2

= 6x9.9^2

≈588.06in^2
4 0
4 years ago
I need help ASAP, find the area of the trapezoid below
Nata [24]

Answer:

28.

Step-by-step explanation:

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3 0
3 years ago
The difference between the roots of the quadratic equation x2+x+c=0 is 6. Find c.
NemiM [27]
We have that
x_{1} - x_{2} = 6
Let y be the first root, then y - 6 will be the second one. Since both roots make the quadratic equation equal to 0, we have that:
y^{2}  + y + c =  (y - 6)^{2}  + (y - 6) +c
Solve for y:
y^{2} +y +c = y^{2} - 12y + 36 + y - 6 +c \\ y + 12y - y = 30 \\ y =  \frac{5}{2}
Plug in y = 5/2 into original quadratic equation and solve for c:
(  \frac{5}{2}) ^{2} +  \frac{5}{2}  +c = 0 \\  c= - \frac{5}{2}  -  \frac{25}{4}  \\ c = - \frac{35}{4}
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6 0
4 years ago
Which is one of the solutions to the equation 2x^2 - x - 4 = 0
Alex73 [517]

Answer:

x_{1}=\frac{1+\sqrt{33} }{4}\\x_{2}=\frac{1-\sqrt{33} }{4}

Step-by-step explanation:

Using quadratic formula

x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}

we will have two solutions.

2x^2 - x - 4 = 0

So, a=2   b=-1  c=-4, we have:

x_{1}=\frac{+1+\sqrt{-1^{2}-4*2*-4} }{2*2}\\\\x_{2}=\frac{+1-\sqrt{-1^{2}-4*2*-4} }{2*2}

Finally, we have two solutions:

x_{1}=\frac{1+\sqrt{33} }{4}\\\\x_{2}=\frac{1-\sqrt{33} }{4}

5 0
4 years ago
Solve 9x – 8 = 6x + 4
Agata [3.3K]

Answer:

Step-by-step explanation:

9x - 8 = 6x + 4

3x - 8 = 4

3x = 12

x = 4

4 0
3 years ago
Read 2 more answers
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