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kenny6666 [7]
3 years ago
6

I need help with this Pythagorean Theorem. ​

Mathematics
1 answer:
sasho [114]3 years ago
6 0
The answer is C= 11.42
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Match each question to the correct problem.
Maslowich
<h2>Answer:</h2>

<em>(Check attached images).</em>

<h2>Step-by-step explanation:</h2>

<h3>Exercise 1.</h3>

a. Convert to decimals.

To order the numbers from least to greaters, convert them to decimals and compare.

5.2(percent)=0.052\\ \\\frac{1}{7} =0.1429\\\\ -0.8=-0.8000\\ \\\frac{-11}{5} =-2.2

b. Select the second least number.

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<h3>Exercise 2.</h3>

a. Convert to decimals.

-3.4(percent)=-0.034\\ \\-0.031\\\\ -0.2\\ \\-\sqrt{0.8}= -0.8944

b. Select the correct number.

-\frac{1}{5}.

<h3>Exercise 3.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

<em>59%=0.59</em>

<em>3/5=0.6</em>

<em />

b. Select the correct number.

3/5.

<h3>Exercise 4.</h3>

a. Convert to decimals.

-0.35

-3.5%= -0.035

b. Conclude.

Seeing that -3.5% is less than -0.35, the symbol that makes the statement true is ">".

<h3>Exercise 5.</h3>

a. Try to visually estimate b.

B appears to have a value of -0.9.

b. Convert the numbers to decimals.

-3.4%= -0.034

-0.031

-1/5= -0.2

-\sqrt{0.8}= -0.8944

c. Select the correct answer.

<em>Since we estimated the value of b as -0.9, the number that best adequates to its value is </em>-\sqrt{0.8}.

<h3>Exercise 6.</h3>

a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the positive numbers.</em>

5.2%= 0.052

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b. Select the correct number.

5.2% is the second largest.

<h3>Exercise 7.</h3>

a. Convert to decimals.

6/7= 0.857143

0.857

b. Select the correct answer.

Seeing that 0.857 is marked as an approximate by the

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a. Convert to decimals.

<em>After seeing that there are negative and positive numbers, and with the premise that negative numbers are </em><u><em>always</em></u><em> lesser than positive numbers, we'll only compare the negative numbers.</em>

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