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Leno4ka [110]
3 years ago
8

The scale on a map indicates that 1 inch corresponds to an actual distance of 95 miles. two cities are 4.5 inches apart on the m

ap. what is the actual distance between the two cities?
Mathematics
1 answer:
arlik [135]3 years ago
3 0
The two cities are actually 427.5 miles apart.
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An apartment complex on Ferenginar with 250 units currently has 223 occupants. The current rent for a unit is 892 slips of Gold-
Triss [41]

Answer:

Step-by-step explanation:

Given data

Total units = 250

Current occupants = 223

Rent per unit = 892 slips of Gold-Pressed latinum

Current rent = 892 x 223 =198,916 slips of Gold-Pressed latinum

After increase in the rent, then the rent function becomes

Let us conside 'y' is increased in amount of rent

Then occupants left will be [223 - y]

Rent = [892 + 2y][223 - y] = R[y]

To maximize rent =

\frac{dR}{dy}=0\\=2(223-y)-(892+2y)=0\\=446-2y-892-2y=0\\=-446-4y=0\\y=\frac{-446}{4}=-111.5

Since 'y' comes in negative, the owner must decrease his rent to maximixe profit.

Since there are only 250 units available;

y=-250+223=-27\\\\maximum \,profit =[892+2(-27)][223+27]\\=838 * 250\\=838\,for\,250\,units

Optimal rent - 838 slips of Gold-Pressed latinum

8 0
3 years ago
Suppose​ a, b, and c are all negative numbers. How do you find the distance between the points​ (a,b) and​ (a,c)?
Alex787 [66]

Answer:

E

Step-by-step explanation:

Let's say if b = -2 and c = -3

-2-(-3) = 1 that would be the distance between them.  If it was D then you would need absolute value.

Hope this helps!  Have a nice day!

4 0
3 years ago
11 = − 3k − 22 − 8k<br> K equals what?
butalik [34]

  11 = -3k - 22 - 8k

  11 = -11k - 22         <em>added like terms (-3k and -8k)</em>

<u>+22</u>     <u>     +22 </u>

33 = -11k

\frac{33}{-11} = \frac{-11k}{-11}

 -3 = k

Answer: k = -3

3 0
3 years ago
A. Jenna wants to buy a new tablet computer. Top Quality, an electronics store, is selling them at a 15% discount off the list p
marissa [1.9K]

Answer:

Step-by-step explanation:

Part A

Cost = T - (15/100) * T

Cost = (85/100)*T

Part B

You are asked to take 15% off the cost of something. The first equation is very clear how to do that -- just take 15% of T away from T

The second part is not so obvious if you are not familiar with it, but the result will be the same.

Start with the first equation

Cost = T - (15/100) T  Change 1 T to 100 / 100

Cost = 100*T/100T - 15/100T

Cost = 85 /100 * T

Part C

Cost = Phone - 14            at Top quality.     Red in Graph below

Cost = 75/100 * Phone    at Big value.        Blue in Graph belos

The graph below is a good way to answer this. I won't solve it algebraically when the graph will give you a much better idea which phone to get.

Answer: Up to a phone cost of 55 dollars, the red phone is the better buy.

After 55$ the blue phone is better.

Try this with a couple of values for phone,

4 0
3 years ago
I need help with this one please. 5X=1/2(3x-2)
Sholpan [36]
X = -2/7
5x = 1/2 ( 3x - 2 )
5x = 1.5x - 1
3.5x = -1
x = -2/7
4 0
3 years ago
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