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2 years ago

if a rectangle is 8 in long and 6 in wide how many one square inch tikes are needed to cover its area

Mathematics

1 answer:

zimovet [89]2 years ago

8 0

Answer:48 one square inch tiles

Step-by-step explanation:

The square has an area of (8x6)=48in^2. If we place 1 in^2 square tiles in a line 8 across (8 inches) and 6 down (6 inches), there will be 8x6 = 48 one square inch tiles.

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From 1940 to 1980, the consumer price index (CPI) increased from 28.6 to 89.4. If a gallon of milk cost $0.75 in 1940 and the pr

devlian [24]

28.6 / 89.4 = 0.75 / x
cross multiply
28.6x = 67.05
x = 67.05 / 28.6
x = 2.34 <==

5 0

2 years ago

a metal cube measures 2-centimeters on each side the mass of the cube is 72 grams what is the density of the metal cube

Umnica [9.8K]

Answer:

9 gram/cm³

Step-by-step explanation:

Volume of a square (L³) = 2³ = 8cm³

But Density = mass/volume

But Density = Mass/Volume

Density = 72grams/8cm³

Density = 9grams/cm³

8 0

3 years ago

The coordinates of point P on a coordinate grid are (−5, −6). Point P is reflected across the y-axis to obtain point Q and acros

Scilla [17]

Reflection of point (x ,y) about x axis is given by (x,-y) and about y axis is given by (-x,y) .treat the line as plane mirror about which you have to find out point reflection .thus Q is (5 ,-6) and R is(-5,6)..

5 0

3 years ago

What is 1/4 times 2 -9

krek1111 [17]

Answer:

-8.5

Step-by-step explanation:

1/4 times 2= 0.5

0.5-9=-8.5

Hope this helps :D

5 0

3 years ago

Read 2 more answers

A boy has 3 red , 2 yellow and 3 green marbles. In how many ways can the boy arrange the marbles in a line if: a) Marbles of the

Ilya [14]

Answer:

The total number of different arrangements is 560.

Step-by-step explanation:

A multiset is a collection of objects, just like a set, but can contain an object more than once.

The multiplicity of a particular type of object is the number of times objects of that type appear in a multiset.

Permutations of Multisets Theorem.

The number of ordered n-tuples (or permutations with repetition) on a collection or multiset of $n$ objects, where there are $k$ kinds of objects and object kind 1 occurs with multiplicity $n_1$ , object kind 2 occurs with multiplicity $n_2$ , ... , and object kind $k$ occurs with multiplicity $n_k$ is:

$\begin{equation*}\frac{n!}{n_1!*n_2!*\dots * n_k!}\end{equation*}$

We know that a boy has 3 red, 2 yellow and 3 green marbles. In this case we have n = 8.

If marbles of the same color are indistinguishable, then the total number of different arrangements is

${8 \choose 3, 2, 3} = \frac{8 !}{3 ! 2 ! 3 !} = \frac{8\cdot \:7\cdot \:6\cdot \:5\cdot \:4}{2!\cdot \:3!}=\frac{6720}{2!\cdot \:3!}=\frac{6720}{12}=560$

8 0

2 years ago