Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
20 will be the answer
you've to remove decimal from the sum.
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Answer:
<u>Same side angles are supplementary</u>
L+k=180
18x-18+72=180
18x=126
x=7
m∠18(7)-18
= 108°
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hope it helps...
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Answer:

Step-by-step explanation:
Simplify the radical by breaking the radicand up into a product of known factors.
Like this :
Answer:
x = 11/2 = 5.5
Step-by-step explanation:
2x-6 = 5
2x = 11
x = 11/2 = 5.5