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Alika [10]
3 years ago
5

One winter, a group of students measured snowfall totals at their school. This chart shows how many inches of snow the students

measured each month How much total snowfall did they receive at their school that winter?
month. snowfall
December 4.2
January. 8.9
February. 5.4​
Mathematics
1 answer:
Hatshy [7]3 years ago
5 0

Answer: 18.5 inches

Step-by-step explanation:

The total snowfall that the students received at their school that winter will be the addition of the snowfall for each month and this will be:

= December snowfall + January snowfall + February snowfall

= 4.2 + 8.9 + 5.4

= 18.5

The total snowfall is 18.9 inches.

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1/3 times 3/4 times 1/3 as a fraction so basically what is 0.08333333333 as a fraction
SpyIntel [72]

Answer:

mark me brainliest

Step-by-step explanation:

To write 0.08333333333 as a fraction you have to write 0.08333333333 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.08333333333 = 0.08333333333/1 = 0.8333333333/10 = 8.333333333/100 = 83.33333333/1000 = 833.3333333/10000 = 8333.333333/100000 = 83333.33333/1000000 = 833333.3333/10000000 = 8333333.333/100000000 = 83333333.33/1000000000 = 833333333.3/10000000000 = 8333333333/100000000000

And finally we have:

0.08333333333 as a fraction equals 8333333333/100000000000

7 0
2 years ago
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In order to either condense or expand logarithms using their properties, what must be?
jasenka [17]

Answer:

Answer C

Step-by-step explanation:

The rules of logarithmic functions require the two log functions to have the same base. If they do not have the same base, you cannot apply any of the rules.

5 0
1 year ago
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HELP!!! solve the following system:<br>y = x + 3<br>3x + y = 19
MariettaO [177]
3x + (x+3) = 19
4x + 3 = 19
4x = 16
x = 4

y= x+3
y= 4+3
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8 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
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3 years ago
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