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solniwko [45]
3 years ago
8

The length of a rectangle is 5 less than twice the width. If the perimeter of the rectangle is 146 cm, find the dimensions of th

e rectangle.
what would the length and width be?
Mathematics
1 answer:
Marta_Voda [28]3 years ago
4 0

Length = 2x - 5

Width = x

Perimeter = 146

P = 2L + 2W

146 = 2(2x - 5) + 2x

146 = 4x - 10 + 2x

146 = 6x - 10

146 + 10 = 6x

156 = 6x

156/6 = x

26 = x

Length = 2(26) - 5

Length = 52 - 5

Length = 47 cm

Width = x

Width = 26 cm

Did you follow?

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Ayuda necesitó esto lo mas pronto posible :cc
matrenka [14]

Answer:

La densidad del líquido desconocido es de aproximadamente 0,6855 g/ml.

Step-by-step explanation:

Los parámetros dados son;

La masa del recipiente vacío = 38,52 g

La masa total del recipiente cuando está lleno de agua = 137,26 g

La masa total del recipiente cuando se llena con el líquido desconocido = 106.21 g

Por lo tanto;

La masa del agua = La masa total del recipiente cuando está lleno de agua - La masa del recipiente vacío

La masa del agua = 137,26 g - 38,52 g = 98,74 g

La masa del líquido desconocido = 106,21 g - 38,52 g = 67,69 g

La gravedad específica del líquido desconocido = (La densidad de la sustancia desconocida) / (La densidad del agua)

De lo que tenemos;

La gravedad específica del líquido desconocido = (La masa del líquido desconocido) / (La masa de un volumen igual de agua)

∴ La gravedad específica del líquido desconocido = (67,69 g) / (98,74 g) ≈ 0,6855

De la ecuación, gravedad específica = (La densidad del líquido desconocido) / (La densidad del agua) y la densidad del agua = 1 g / ml, tenemos;

gravedad específica ≈ 0.6855 = (La densidad del líquido desconocido) / (1 g / ml)

La densidad del líquido desconocido ≈ 0.6855 × 1 g / ml ≈ 0.6855 g / ml

La densidad del líquido desconocido ≈ 0,6855 g / ml.

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