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juin [17]
3 years ago
8

Have no clue what to do

Mathematics
1 answer:
WITCHER [35]3 years ago
3 0
It says that the value of a box above two boxes is found by adding the expressions in the two boxes.  I filled in the boxes.  The top box is 13x + 30, or option B.

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Write the square roots of 49 i in ascending order of the angle.
Troyanec [42]

Answer:

The square roots of 49·i in ascending order are;

1) -7·(cos(45°) + i·sin(45°))

2) 7·(cos(45°) + i·sin(45°))

Step-by-step explanation:

The square root of complex numbers 49·i is found as follows;

x + y·i = r·(cosθ + i·sinθ)

Where;

r = √(x² + y²)

θ = arctan(y/x)

Therefore;

49·i = 0 + 49·i

Therefore, we have;

r = √(0² + 49²) = 49

θ = arctan(49/0) → 90°

Therefore, we have;

49·i = 49·(cos(90°) + i·sin(90°)

By De Moivre's formula, we have;

r \cdot (cos(\theta) + i \cdot sin(\theta) )^{\dfrac{1}{2}}  =  \pm \sqrt{r} \cdot \left (cos\left (\dfrac{\theta}{2} \right ) + i \cdot sin\left (\dfrac{\theta}{2} \right ) \right )

Therefore;

√(49·i) = √(49·(cos(90°) + i·sin(90°)) = ± √49·(cos(90°/2) + i·sin(90°/2))

∴ √(49·i) = ± √49·(cos(90°/2) + i·sin(90°/2)) = ± 7·(cos(45°) + i·sin(45°))

√(49·i) = ± 7·(cos(45°) + i·sin(45°))

The square roots of 49·i in ascending order are;

√(49·i) = - 7·(cos(45°) + i·sin(45°))  and  7·(cos(45°) + i·sin(45°))

8 0
2 years ago
Need help with this problem on homework
mylen [45]
The answer is 2x - 2
5 0
3 years ago
206.8<br> × .42 need help I keep coming up with the wrong answer dont know what I'm doing wrong
aleksklad [387]
86.856 should be the correct answer
4 0
3 years ago
Read 2 more answers
A collector has 120 movie posters and 100 band posters. She wants to sell 24 movie posters but still have her poster collection
Serga [27]

Answer:

She must sell 20 band posters

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which expressions show the expanded form for 50.029?
Anna [14]
They all show 50.029
The correct answers are:
A.) <span>5 × 10 + 0 × 1 + 0 × 1/10 + 2 ×1/100 + 9 × 1/1000 
Sorry.
This is all I can find correct
Its a little hard when you post the tenths, hundredths, and thousandths as fractions, but A is all I can find.

</span>
8 0
3 years ago
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