Answer:
0.95 = 95% probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS
Step-by-step explanation:
We solve this question treating these probabilities as Venn sets.
I am going to say that:
Event A: Requesting automatic transmission
Event B: Requesting built-in GPS
90% of all buyers request automatic transmission
This means that 
82% of all buyers request built-in GPS
This means that 
77% of all buyers request both automatic transmission and built-in GPS.
This means that 
What is the probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS
This is 
, which is given by:
So
0.95 = 95% probability that the next person to purchase this car will request at least one of automatic transmission or built-in GPS
Whoever scored 72 shots out of 150. Did, In fact, score 48% of their shots.
Solution:
*To calculate the percentage represented by a ratio simply divide the numerator by the denominator and multiply by 100.
72:150 (72/150)
72/150
= 0.48
0.48(100) = 48
... 48%
Answer:
D
Step-by-step explanation:
other options lie outside the domain and range
Answer:16×16×16
Step-by-step explanaution:
16 ^3 so that means you need to but 16 3 times
recalling that d = rt, distance = rate * time.
we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?
so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.
then Wanda kicks in, rolling like a lightning at 16mph.
let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.
the distance both have travelled is the same "d" miles, reason why they "meet", same distance.
![\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blcccl%7D%20%26%5Cstackrel%7Bmiles%7D%7Bdistance%7D%26%5Cstackrel%7Bmph%7D%7Brate%7D%26%5Cstackrel%7Bhours%7D%7Btime%7D%5C%5C%20%5Ccline%7B2-4%7D%26%5C%5C%20Hector%26d%2612%26t%2B%5Cfrac%7B3%7D%7B2%7D%5C%5C%5B1em%5D%20Wanda%26d%2616%26t%20%5Cend%7Barray%7D%5Cqquad%20%5Cimplies%20%5Cbegin%7Bcases%7D%20%5Cboxed%7Bd%7D%3D%2812%29%5Cleft%28%20t%2B%5Cfrac%7B3%7D%7B2%7D%20%5Cright%29%5C%5C%5B1em%5D%20d%3D%2816%29%28t%29%20%5Cend%7Bcases%7D)
