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3 years ago

What is the volume of the rectangular prism below?

Mathematics

2 answers:

KiRa [710]3 years ago

6 0

Answer:

What rectangular prism?

Step-by-step explanation:

Please mark as Brainliest! :)

Have a nice day.

VMariaS [17]3 years ago

6 0

Answer:

24m^3

Step-by-step explanation:

Volume of Rectangular Prism: lwh

Length: 4

Width: 2

Height: 3

Volume: 4 x 2 x 3

Volume: 8 x 3

Volume: 24m^3

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How do you know if an number composite or not

cestrela7 [59]

Answer:

A prime number has only two factors: 1 and itself. A composite number has more than two factors

Step-by-step explanation:

Can i have a thanks?

3 0

2 years ago

A blueprint for a house states that 2.5 inches equal 10 feet. If the length of a wall is 12 feet how many inches is the wall in

Xelga [282]

If 10 feet = 2.5 inches
then 1 feet = 2.5/10 = 0.25
therefore 12 feet = 3 inches

In short the answer is 3 inches on the blueprint

4 0

3 years ago

Shubham, Ashish, and Vinay participated in a long jump competition on their sports day. Shubham jumped 41 m 2 , while Ashish jum

9966 [12]

Answer:

Vinay jumped = 49m

Step-by-step explanation:

Given:

Shubham jumped = 41m

Ashish jumped = 3m less than Shubham

Vinay jumped = 11m more than Ashish

Find:

Length of Viney's jump

Computation:

Ashish jumped = Shubham jumped - 3m

Ashish jumped = 41m - 3m

Ashish jumped = 38m

Vinay jumped = Ashish jumped + 11m

Vinay jumped = 38m + 11m

Vinay jumped = 49m

6 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

2 years ago

X^3 = ? Please write the answer correctly.

photoshop1234 [79]

Answer: (x)(x)(x) = x^3.

Step-by-step explanation:

x^3 means multiply x by it's self 3 times.

Hope this helps..

4 0

3 years ago

Read 2 more answers