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2 years ago

Please answer fast, will give brainliest!

Mathematics

1 answer:

9966 [12]2 years ago

4 0

Answer:

the third one

Step-by-step explanation:

x^2 is always non-negative, so -3x^2 will always be non-positive. You can eliminate any tables with positive values for y.

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14x+7y=217 14x+3y=189

kondor19780726 [428]

Answer:

y = 7

x = 12

Step-by-step explanation:

14x+7y=217, then 14x = 217 - 7y

14x+3y=189, then 14x = 189 - 3y

217 - 7y = 189 - 3y

add 7y to each side of the equation:

4y + 189 = 217

subtract 1890 from each side:

4y = 28

divide both sides by 4:

y = 7

14x + 3(7) = 189

subtract 21 from each side:

14x = 168

divide both sides by 14:

x = 12

4 0

3 years ago

Maureen bought cupcakes for her sister's birthday party. 40% of the 95 cupcakes had

Tanzania [10]

Answer:

34 cupcakes

Step-by-step explanation:

We know that:

40/100 x 95

Work:

40/100 x 95
=> 2/5 x 95
=> 2 x 17
=> 34 cupcakes

Hence, 34 cupcakes had sprinkles.

8 0

2 years ago

A: x/4 +1 = -3 B: x+4 = -12 1) How can we get Equation B from Equation A?

Sveta_85 [38]

Answer:In the equation y = mx + b for a straight line, the number m is called the slope of the line. Let x = 0, then y = m • 0 + b, so y = b. The number b is the coordinate on the y-axis where the graph crosses the y-axi

Step-by-step explanation:

5 0

3 years ago

How do you find the quotient of 2 fractions? E.g, 3/5 and 9/10.

liq [111]

Answer:

by dividing the fractions

4 0

2 years ago

Read 2 more answers

The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0

3 years ago