Question

Solve the quadratic equation 3x²+2x-4=0

Answer 1

Answer:

Step-by-step explanation:

Hello,

$\Delta = 2^2-4*3*(-4)= 4+48=52$

so the two solutions are

$\dfrac{-2+2\sqrt{13}}{2*3}=\dfrac{\sqrt{13}-1}{3}=0.87\\\\\dfrac{-2-2\sqrt{13}}{2*3}=-\dfrac{\sqrt{13}+1}{3}=-1.54$