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UkoKoshka [18]
3 years ago
6

Solve the quadratic equation 3x²+2x-4=0

Mathematics
1 answer:
steposvetlana [31]3 years ago
5 0

Answer:

Step-by-step explanation:

Hello,

\Delta = 2^2-4*3*(-4)= 4+48=52

so the two solutions are

\dfrac{-2+2\sqrt{13}}{2*3}=\dfrac{\sqrt{13}-1}{3}=0.87\\\\\dfrac{-2-2\sqrt{13}}{2*3}=-\dfrac{\sqrt{13}+1}{3}=-1.54\\\\

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