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3 years ago

15 points! Please help!

Mathematics

1 answer:

Setler [38]3 years ago

5 0

Answer:

1/3x - 1/4y - 4/5 + 1/3x -1/4y

Step-by-step explanation:

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4 over 5 in standard form

postnew [5]

Answer:0.8

Step-by-step explanation:

it is basically 10 times 8 to the power of -1

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3 years ago

What is the square root of 529

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

Because 23•23=529 so the square root of 529 is 23.

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3 years ago

If i have 64,32,16,8 what two numbers comes next

monitta

4 and 2.
(Because the pattern is that it is dividing the previous number by 2)

Sample text because sample text is sample text, which is sample text according to sample text.

8 0

3 years ago

Read 2 more answers

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

3 years ago

I need help writing an equation for this question. i would be very grateful for help. And if you do help thank you very much.

Neko [114]

2525 + 33x If I helped please leave a 5 star review and hit the thanks button.

8 0

3 years ago