Answer:
im sorry but i dont understand what your say can you be more specific
Step-by-step explanation:
Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
To make the exponent positive, make a fraction. 1/3 * 1/3. This is 0.1 repeating. 3^1 is 3. So the answer is no.
<span>pennies = 0.01 $
nickels = 0.05 $
dimes = 0.1 $
quarters = 0.25 $
We must write the system of equations that best suits this problem and solve it:
Let:
x = pennies
y = nickels
z = dimes
w = quarters
Writing the equations
0.01x + 0.05y + 0.1z + 0.25w = 3.71
I have twice as many dimes as nickels
z = 2y
two more nickels than quarters
y = w + 2
three fewer pennies than three times the number of nickels
x = 3y-3.
Solving the system of equations:
x = 21
y = 8
z = 16
w = 6
answer
He has
21 pennies
8 nickels
16 dimes
6 quarters
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