The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
5 miles
You can use the special right triangles for this equation. Since the side lengths are 3 and 4, the hypotenuse of the triangle would be 5, or you can use the equation a2 + b2 = c2, 3^2 + 4^2 = c2, 25 = c2, c=5
Answer:
Step-by-step explanation:
You know these ordered pairs are considered a function, because the x intercepts do not repeat themselves. In other words, each input numbers are different. If these ordered pairs were not a function, the x intercept would be repeating. For example, 22 is already a x intercept, (22,4), if 22 was put in as another x intercept like,(22,1) these ordered pairs would not be a function.
Answer: 4(−a+1)(a−1)
Step-by-step explanation:
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