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svp [43]
3 years ago
5

3. Which scenarios will have a quotient of 4/12?​

Mathematics
1 answer:
Andreyy893 years ago
7 0

Answer:

1

Step-by-step explanation:

Divide it and you'll get 1 always

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Find the height of a triangle whose <br>Area=64dm<br>Base=1.6m​
Stella [2.4K]

Answer:

102.4?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Suppose a sample of 972972 tenth graders is drawn. Of the students sampled, 700700 read above the eighth grade level. Using the
max2010maxim [7]

Answer:

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

972 students, 700 read above the eight grade level. We want the confidence interver for the proportion of those who read at or below the 8th grade level. 972 - 700 = 272, so n = 972, \pi = \frac{272}{972} = 0.28

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.259

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.301

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

3 0
3 years ago
A triangle has one side that measures 5 ft, one side that measures 8 ft, and one side that measures 11 ft.
DanielleElmas [232]

an Obtuse angle. Idk what you want.

5 0
3 years ago
A. 36<br> B. 12<br> C. 80<br> D. 60<br> E. 48<br> F. 20
Art [367]

Answer:

it's d because it's correct

Step-by-step explanation:

6 0
3 years ago
the value of a new automobile depreciates 15% during the first year, and 16% during the second year. What is its depreciated val
Flauer [41]
It starts at 100% - 15% = 85% after the first year. $15,000*0.85 = $12,750
The second year is further reduced 100% - 16% = 84%
$12,750*0.84 = $10,710


3 0
3 years ago
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