<h2>
Answer:</h2>
<em><u>The truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>
<h2>
Step-by-step explanation:</h2>
In the question,
The maximum height of the vehicle which is capable of passing under the bridge is 12 feet and 5 inches.
So,
Now we know that,
1 feet = 12 inches
So,
12 feet = 12 x 12 = 144 inches
So,
Total height of the vehicle which is permissible to pass under the bridge is,
12 feet 5 inches = 144 + 5 = 149 inches
Also,
Height of the truck = 162 inches
Therefore, we can see that the permissible height is smaller than the height of the vehicle.
Height of vehicle which is more than permissible height is by,
162 - 149 = 13 inches
<em><u>Therefore, the truck cannot pass safely under the bridge. The truck is 13 inches taller than the maximum height.</u></em>
Answer:
9x2−x4+y(x2+9)2x(x2+9)2
Step-by-step explanation:
Answer:
Probability that a car need to be repaired once = 20% = 0.20
Probability that a car need to be repaired twice = 8% = 0.08
Probability that a car need to be repaired three or more = 2% = 0.02
a) If you own two cars what is the probability that neither will need repair?
Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3
Probability that car need no repair = 1-0.3=0.7
Neither car will need repair=
b) both will need repair?
Probability both will need repair = 
c)at least one car will need repair
Neither car will need repair=
Probability that at least one car will need repair= 1-0.49 = 0.51
2|3x + 5| = -10 . Divide both sides by 2:
|3x + 5| = -5 ===>3x+5=-5 & -3x-5=-5 In both cases x=0
Answer:
45
Step-by-step explanation:
The first part of the question is to throw you off and is of no use
To find the answer you must find the midpoint of 30 and 60
which shall give you 45 and that is the answer to the question
Hope this helped you
