Ideally you would graph the system of linear equations <span>y = -7/4x + 5/2 y = 3/4x – 3 yourself, and then determine the approx. coordinates of their point of intersection.
Your system, </span><span>y = -7/4x + 5/2 y = 3/4x – 3, should be written as:
</span><span>y = (-7/4)x + (5/2) y = (3/4)x – 3
It is important that you put no more than one function on each line.
To solve this system algebraically, set y = y: (-7/4)x + 10/4 = (3/4)x - 3
Now mult all terms by 4 to elim. fractions:
-7x + 10 = 3x - 12
Then 10 = 3x + 7x - 12, or 10 = 10x - 12, or 10x = 22; x is 2.2.
You can now find y by subbing 2.2 for x in either of the given equations.
The solution will have the form (2.2, y).
Once again, note that you were asked to solve this system by graphing.
Graph:
</span>y = (-7/4)x + (5/2) y = (3/4)x – 3
and then determine approx. the coordinates of the pt. of intersection.
Perimeter : because there are four sides to a square and all sides are the same, the answer is 4(2x-9) area: area is basically length times width so the answer is (2x-9)(2x-9) or (2x-9)^2