A regular hexagon can be dissected into six equilateral triangles by adding a center point
We know that
If the scalar product of two vectors<span> is zero, both vectors are </span><span>orthogonal
</span><span>A. (-2,5)
</span>(-2,5)*(1,5)-------> -2*1+5*5=23-----------> <span>are not orthogonal
</span><span>B. (10,-2)
</span>(10,-2)*(1,5)-------> 10*1-2*5=0-----------> are orthogonal
<span>C. (-1,-5)
</span>(-1,-5)*(1,5)-------> -1*1-5*5=-26-----------> are not orthogonal
<span>D. (-5,1)
</span>(-5,1)*(1,5)-------> -5*1+1*5=0-----------> are orthogonal
the answer is
B. (10,-2) and D. (-5,1) are orthogonal to (1,5)
Answer:
-6.25 tI am not sure if this can help you but this is what I got
<span>Any point in figure A can be mapped to a point in figure B.</span>
Answer:
<em><u>In the graph locate the point (3,0) and draw a line parrallel to Y-axis passing through (3,0) .</u></em>
<em><u>Then your line will cut the graph of f(x) at some point, that point's y-coordinate will be your value of f(3).</u></em>
Step-by-step explanation:
Hope it helps!
