If i save 20$ every week for a year how much will i have at the end of the year

2 answers:

7 0

There is 52 weeks in 1 year

Multiply 20 to 52

20 x 52 = 1040

If you save $20 every week for a year, you will have $1040 at the end of the year

hope this helps

wlad13 [49]2 years ago

4 0

If you save $20 every week for a year you will save $1,042.858
Please give me the brainliest answer! <3

You might be interested in

Please help me, I really dont want to get an F :((( (The Graph Is In The Image)

AveGali [126]

Answer: correct answer is B

Step-by-step explanation: I know this because for example if you run one mile it will take you less time than it would if you walked 1 mile

7 0

3 years ago

Five members of the computer club site to buy used computer dividing up the cost equally later three new members join a club of

BartSMP [9]

The computation shows that the price of the used computer is $75.

<h3>How to compute the price?</h3>

From the information given, it should be noted that there are 5 members before the new members joined and $15 was given to each member.

Therefore, the price of the used computer will be:

= $15 × 5

= $75

The price of the used computer is $75.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

7 0

1 year ago

Can someone be my friend

marta [7]

Answer: yes

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Multiply: (2x2 − 5x)(4x2 − 12x + 10)

11Alexandr11 [23.1K]

(2x^2-5x)(4x^2-12x+10) = <span>8x^4 - 44x^3 + 80x^2 - 50x

So, the answer is option C.</span>

5 0

3 years ago

A $250,000 home loan is used to purchase a house. The loan is for 30 years and has a 5.4% APR. Use the amortization formula to d

wlad13 [49]

$\bf ~~~~~~~~~~~~ \textit{Amortized Loan Value}
\\\\
pymt=P\left[ \cfrac{\frac{r}{n}}{1-\left( 1+ \frac{r}{n}\right)^{-nt}} \right]
\\\\\\
~~~~~~
\begin{cases}
P=
\begin{array}{llll}
\textit{original amount deposited}\\
\end{array}\to &250000\\
pymt=\textit{periodic payments}\\
r=rate\to 5.4\%\to \frac{5.4}{100}\to &0.054\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{since the payments are}\\
\textit{monthly, then twelve}
\end{array}\to &12\\
t=years\to &30
\end{cases}
$

$\bf pymt=250000\left[ \cfrac{\frac{0.054}{12}}{1-\left( 1+ \frac{0.054}{12}\right)^{-12\cdot 30}} \right]
\\\\\\
pymt=250000\left[ \cfrac{0.0045}{1-\left( 1.0045\right)^{-360}} \right]
\\\\\\
pymt\approx 250000\left[ \cfrac{0.0045}{0.80138080852472389274} \right]$

8 0

3 years ago