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2 years ago

A parabola has a minimum value of 0, a y-intercept of 4, and an axis of symmetry at x = -2

1 answer:

3 0

Since the minimum value is 0 and axis of symmetry is -2 this means that the vertex is at -2,0 now with the y intercept of 4. You can now plug the values into Vertex form which will be y=a(x-h)^2+k. a being the shrink or stretch of the parabola, h being the x value of the vertex, and k being the y value of the vertex. with all of that plugged in it should look like y=(x+2)^2. You can check this equation by plugging in 0 as x which should find the y intercept of 4. So it should then look like y=(0+2)^2 -> y=(2)^2 -> y=4

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Find the x- and y- intercepts of parabola y=5x^2-16x+10

____ [38]

Y-INTERCEPT

$y = 5x^2 - 16x + 10$

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

$\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10$

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

$y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0$

We need to use the quadratic formula

The quadratic formula helps us find what values of $x$ make the equation = 0

Quadratic formula: $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\$

The x-intercepts are at:

$(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)$

5 0

1 year ago

A small garden measures 8 ft by 7 ft. A uniform border around the garden increases the total area to 110 ft 2. What is the width

Alik [6]

Answer: 3

Step-by-step explanation:

You can answer this question by using the equation

(8+x)(7+x)=110

The x represents the width, as we do not know the area. If you simplify the equation, it becomes 56+15x+x2=110.

If you move all the terms to the left side, and rearrange it, it can become x^2+15x-54=0

This can be simplified into (x-3)(x+18)=0

This equation makes it so that x is either 3 or -18. It is not possible for a width to be -18, so the width must be 3.

8 0

3 years ago

Help!! (Algebra II Matrices and Determinants)

bagirrra123 [75]

Answer:

Option A

Step-by-step explanation:

5 0

3 years ago

How do you multiply fractions

dexar [7]

This really depends on the fraction; if there are variables in the equation, if they are full numbers,etc. I'd really recommend looking up khan academy on YouTube and that will really help you out!

4 0

3 years ago

Select all of the points that are solutions to the system of linear inequalities that is listed below 10x + 4y < 12 8x -3y &g

liberstina [14]

Answer:

(3, -8) and (2, -10)

Step-by-step explanation:

Given

$10x + 4y < 12$