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KIM [24]
3 years ago
15

A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. if customers choose one salad, o

ne main course and two different desserts for their meal, how many different meals are possible?
Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0

8\cdot5\cdot C(6,2)=40\cdot\dfrac{6!}{2!3!}=40\cdot\dfrac{4\cdot5\cdot6}{2}=2,400

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What two number multiplies to get 15 and adds to get 6
OverLord2011 [107]
Asking the Math Gods...

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5 0
3 years ago
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Radda [10]

Answer:

B

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3 0
3 years ago
Read 2 more answers
What is the solution to the given inequality?
SashulF [63]

1/2 - 1/4x ≥ -1/4

Combine 1/4x to get x/4:

1/2 - x/4 ≥ -1/4

Subtract 1/2 from both sides:

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Simplify:

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Multiply both sides by 4:

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5 0
3 years ago
Please see below!! Thank you so much in advance :)
stellarik [79]

Answer:

a) x = -1.9, 1.05

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Explanation:

I hope it's correct

7 0
2 years ago
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