2 years ago

A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. if customers choose one salad, o

ne main course and two different desserts for their meal, how many different meals are possible?

1 answer:

4 0

$8\cdot5\cdot C(6,2)=40\cdot\dfrac{6!}{2!3!}=40\cdot\dfrac{4\cdot5\cdot6}{2}=2,400$

You might be interested in

iogann1982 [59]

Answer:

35% off

Step-by-step explanation:

6 0

3 years ago

quester [9]

More than $1137.50 but less than $1327.34

6 0

2 years ago

Archy [21]

Answer:

Step-by-step explanation:

7 0

2 years ago

Vikki [24]

Answer:yes

Step-by-step explanation:

is so yes so if the 50 it was the 40 so then they it yes

3 0

2 years ago

11Alexandr11 [23.1K]

Ok so you would times 8.4*10 and get 84-6 which is 78, and 6.5*10 which is 65-6, so then you get 78+59=137 :)

5 0

2 years ago