3 years ago

A certain restaurant offers 8 different salads, 5 different main courses, 6 different desserts. if customers choose one salad, o

ne main course and two different desserts for their meal, how many different meals are possible?

Mathematics

1 answer:

kobusy [5.1K]3 years ago

4 0

$8\cdot5\cdot C(6,2)=40\cdot\dfrac{6!}{2!3!}=40\cdot\dfrac{4\cdot5\cdot6}{2}=2,400$

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