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e-lub [12.9K]
3 years ago
15

A submarine was cruising at 1,328.4 feet below sea level. It then rose at a rate of 14.76 feet per minute for 15 minutes. Find t

he submarines depth after it rose for 15 minutes.
Mathematics
1 answer:
forsale [732]3 years ago
5 0

Answer:

New depth = 1,107 feet

Step-by-step explanation:

1) Let us first calculate the total number of feet the submarine rose in 15 minutes using the rate of rise.

rate = 14.76 feet per minute

This means that at every minute, the submarine rose by 14.76 feet.

1 minute = 14.76 feet

∴ 15 minutes = 14.76 × 15 = 221.4 feet

2) To find the new depth, we will subtract the number of feet risen from the initial depth.

initial depth = 1,328.4 feet

rise after 15 minutes = 221.4 feet

New depth = 1,328.4 - 221.4 = 1,107 feet

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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  6. Addition
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Equality Properties

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define Systems</u>

x - 2y = 12

5x + 3y = -44

<u>Step 2: Rewrite Systems</u>

x - 2y = 12

  1. [Multiplication Property of Equality] Multiply everything by -5:                  -5x + 10y = -60

<u>Step 3: Redefine Systems</u>

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<u>Step 4: Solve for </u><em><u>y</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                                                                                   13y = -104
  2. [Division Property of Equality] Divide 13 on both sides:                              y = -8

<u>Step 5: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x - 2y = 12
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  4. [Subtraction Property of Equality] Subtract 16 on both sides:                      x = -4
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\huge\bold{To\:find:}

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\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}

\sf\purple{The\:value\:of\:x\:is\:10°. }

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

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\huge\bold{To\:verify :}

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\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.ඞ}}}}}∘

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