You check both of them:
1. 3*3-(-8)/4=9-(-2)=9+2=11 it's true
2. 3*4-4/4=12-1=11 true
so both of them are solutions
3 out of 6 because there are 6 numbers altoghether on a ordinary die and there are 3 odd numbers on that die 1,3, and 5 therefore the answer is 3/6
Answer:
A, D
Step-by-step explanation:
The slope is ...
... m = (change in y)/(change in x) = (5-3)/(6-3) = 2/3
The points are (3, 3) and (6, 5).
The point-slope form of the equation of a line with slope m through (h, k) is ...
... y -k = m(x -h)
In your problem, m = 2/3, eliminating choices B and F.
The points all have positive coordinates, so the x- and y-terms will all have minus signs—eliminating choices B, C, E.
The only remaining choices are A and D, one of which uses one point and the other of which uses the other point. They are both valid choices.
- A. y - 3 = 2/3(x - 3)
- D. y - 5 = 2/3(x - 6)
Step One
Develop Pascal's Triangle
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1 <<<< How the 5th power expands.
Step Two
Confirm that nCr gives the same thing as the triangle gives.
The third term is outlined as 10 a^3 b^2 The powers must add to 5.
The 10 can be found this way
nCr Where n is the row number and r is the term you want so
n = 5
r = 3
nCr = n! / [(n - r)! r!]
5C3 = 5! / ((3!) (2!) )
5C3 = 5 * 4 / 2
5C3 = 10 Just as the triangle predicted.
Step Three
Find a^3 b^2
a = 3x
b = - 5y
a^3 = (3x)^3
a^3 = 27x^3
b^2 = (-5y)^2
b^2 = 25 y^2
Step Three
Find the Answer
Third term = 10*27x^3*25y^2
Third term = 6750 x^3y^2